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In-s [12.5K]
3 years ago
13

The H.C.F and the LCM of two numbers are 36 and 720 respectively. If one of the numbers is 180, which is the other number. *

Mathematics
2 answers:
lutik1710 [3]3 years ago
8 0

Answer:

let p(x)=180

LCM=720

HCF=36

WE HAVE TO FIND q(x)=?

as we know that

p(x)×q(x)=LCM×HCF

NOW WE HAVE TO FIND q(x)

q(x)=LCM×HCF/p(x)

q(x)=720×36/180

q(x)=25920/180

q(x)=144

i hope this will help you

tankabanditka [31]3 years ago
5 0

Answer:

144

Step-by-step explanation:

HCF(a,b)*LCM(a,b)=ab

36*720=180*x

x= 36*720/180

x= 144

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Seventy percent of all vehicles examined at a certain emissions inspection station pass the inspection. Assuming that successive
LenaWriter [7]

Answer:

(a) The probability that all the next three vehicles inspected pass the inspection is 0.343.

(b) The probability that at least 1 of the next three vehicles inspected fail is 0.657.

(c) The probability that exactly 1 of the next three vehicles passes is 0.189.

(d) The probability that at most 1 of the next three vehicles passes is 0.216.

(e) The probability that all 3 vehicle passes given that at least 1 vehicle passes is 0.3525.

Step-by-step explanation:

Let <em>X</em> = number of vehicles that pass the inspection.

The probability of the random variable <em>X</em> is <em>P (X) = 0.70</em>.

(a)

Compute the probability that all the next three vehicles inspected pass the inspection as follows:

P (All 3 vehicles pass) = [P (X)]³

                                    =(0.70)^{3}\\=0.343

Thus, the probability that all the next three vehicles inspected pass the inspection is 0.343.

(b)

Compute the probability that at least 1 of the next three vehicles inspected fail as follows:

P (At least 1 of 3 fails) = 1 - P (All 3 vehicles pass)

                                   =1-0.343\\=0.657

Thus, the probability that at least 1 of the next three vehicles inspected fail is 0.657.

(c)

Compute the probability that exactly 1 of the next three vehicles passes as follows:

P (Exactly one) = P (1st vehicle or 2nd vehicle or 3 vehicle)

                         = P (Only 1st vehicle passes) + P (Only 2nd vehicle passes)

                              + P (Only 3rd vehicle passes)

                       =(0.70\times0.30\times0.30) + (0.30\times0.70\times0.30)+(0.30\times0.30\times0.70)\\=0.189

Thus, the probability that exactly 1 of the next three vehicles passes is 0.189.

(d)

Compute the probability that at most 1 of the next three vehicles passes as follows:

P (At most 1 vehicle passes) = P (Exactly 1 vehicles passes)

                                                       + P (0 vehicles passes)

                                              =0.189+(0.30\times0.30\times0.30)\\=0.216

Thus, the probability that at most 1 of the next three vehicles passes is 0.216.

(e)

Let <em>X</em> = all 3 vehicle passes and <em>Y</em> = at least 1 vehicle passes.

Compute the conditional probability that all 3 vehicle passes given that at least 1 vehicle passes as follows:

P(X|Y)=\frac{P(X\cap Y)}{P(Y)} =\frac{P(X)}{P(Y)} =\frac{(0.70)^{3}}{[1-(0.30)^{3}]} =0.3525

Thus, the probability that all 3 vehicle passes given that at least 1 vehicle passes is 0.3525.

7 0
3 years ago
11. PLS help!!! the question is attached in the image below
Colt1911 [192]

Answer:

y = 3/2x-5/2

Step-by-step explanation:

We have two points so we can write the equation for the line. (-1,-4) and (3,2)

First we can find the slope by using

m= (y2-y1)/(x2-x1)

m = (2- -4)/(3 - -1)

   =(2+4)/(3+1)

   = 6/4

    = 3/2

Then put the slope into the slope intercept form of the equation

y= mx+b  where m is the slope and b is the y intercept

y = 3/2x+b

We will use the point (3,2) and substitute it into the equation to find b

2 = 3/2(3)+b

2 = 9/2 +b

Subtract 9/2 from each side

4/2 -9/2 = 9/2-9/2 +b

-5/2 = b

y = 3/2x-5/2

4 0
3 years ago
WILL MARK THE CORRECT ANSWER BRAINLIEST!<br><br> Select all the correct answers:
stepladder [879]

Answer:

B, D

Step-by-step explanation:

Solve all equations:

A.

x-3x=-2x+4\\ \\-2x=-2x+4\\ \\0=4

This is false equality, so this equation has no solutions.

B.

x-\dfrac{1}{3}(3x)=0\\ \\x-x=0\\ \\0=0

This equality is true for all values of x, so this equation has infinitely many solutions.

C.

\dfrac{1}{3}x-3=4+2x\\ \\x-9=12+6x\\ \\x-6x=12+9\\ \\-5x=21\\ \\x=-\dfrac{21}{5}

This equation has the unique solution.

D.

3x+2-\dfrac{1}{3}(3x)=2+2x\\ \\9x+6-3x=6+6x\\ \\6x+6=6+6x\\ \\0=0

This equality is true for all values of x, so this equation has infinitely many solutions.

E.

x-\dfrac{1}{3}x+2=0\\ \\3x-x+6=0\\ \\2x=-6\\ \\x=-3

This equation has the unique solution.

8 0
3 years ago
Three hundred and eighty -two tenthousandths
AlladinOne [14]

Answer:

382000

Step-by-step explanation:

8 0
3 years ago
Is the equation linear or quadratic?<br> t(x)=x+5<br> O A. linear<br> O B. quadratic
olasank [31]

Answer:

A. Linear

Step-by-step explanation:

The equation (t(x)=x+5) is a linear equation. As per its definition, a linear equation is an equation where all terms are to the first degree, meaning that none of the terms have an exponent. The equation, (t(x)=x+5) falls under this category, as none of its terms has an exponent, therefore, the equation is a linear equation.

4 0
3 years ago
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