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In-s [12.5K]
3 years ago
13

The H.C.F and the LCM of two numbers are 36 and 720 respectively. If one of the numbers is 180, which is the other number. *

Mathematics
2 answers:
lutik1710 [3]3 years ago
8 0

Answer:

let p(x)=180

LCM=720

HCF=36

WE HAVE TO FIND q(x)=?

as we know that

p(x)×q(x)=LCM×HCF

NOW WE HAVE TO FIND q(x)

q(x)=LCM×HCF/p(x)

q(x)=720×36/180

q(x)=25920/180

q(x)=144

i hope this will help you

tankabanditka [31]3 years ago
5 0

Answer:

144

Step-by-step explanation:

HCF(a,b)*LCM(a,b)=ab

36*720=180*x

x= 36*720/180

x= 144

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The correct answer is C. The 13 moose are the individuals. There is one categorical variable and four quantitative variables.

Explanation:

In research, the individuals refer to the participants or population that is being analyzed. For example, if the purpose of the research is to know how many hours highschool students sleep, the individuals are high school students. In this context, the individual or population of this study ae the 13 moose.

Moreover, this research focuses on different variables such as gender, height, the number of hours each moose spends in the water, the weigh of the food eaten on average by each moose, and the average weight of food eaten every day. From these variables, the last four variables are quantitative because they can be measured using numbers, for example, the height is measured in inches. On the other hand, the first variable is categorical because each moose can be classified in only two categories: male or female.

7 0
3 years ago
What is the equation of the line that passes through the points (1,5) and (0,3)?
Pavlova-9 [17]

Answer:

y=2x+3

Step-by-step explanation:

first use the y2-y1/x2-x1 then use y=mx+b after

plug in 3 for y2 and 5 for y1

then plug in 0 for x2 and 1 for x1

\frac{3-5}{0-1}=\frac{-2}{-1} =2 and 2 is ur slope

___________________

now use y=mx+b

i usually use the first point but u can u anyone u want

plug in 1 for x

plug in 5 for y

and plug in 2 for m

5=2(1)+b

5=2+b

subtract 2 on both sides

5-2=3

3=b and b is ur y-intercept

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hope this helps

4 0
3 years ago
What is the value of n?
igor_vitrenko [27]

Answer:

What is n?

Step-by-step explanation:

4 0
3 years ago
18 science club members have birthdays in the summer. This is 20% of the birthdays in the club. How many club members are there?
swat32
18 * 5 = 90
90 represents 100%, because there are 5 20% in 100%

In total there are 90 club members
80% = 71 do not have birthdays in the summer.
8 0
3 years ago
A rectangular parking lot has a length that is 5 yards greater than the width the area of the parking lot is 300 yd.² find the l
ArbitrLikvidat [17]

Answer:

width=5yd and length=10yd

Step-by-step explanation:

To solve this problem, you need to start by asking what you do and don't know (always where to start with word problems)

We know that Area (A) = Length (L) * Width (W)

You know Area (A) = 50 sq. yds.

You don't know anything about the width, so let's just say Width (W) = x

And you know that the length is 5 yds longer than the width, so L = W + 5yd and, since W = x, we can say L = x + 5yd

Now, we recall that A = L * W, and, since A = 50, we can say 50 sq yd = L * W.

Well, now just plug in. What does W equal and L equal?

From above we plug in and can say that 50 sq yd = x * (x + 5 yd).

Multiply it out and you get 50 = x^2 + 5x (removing units for a moment so they don't clutter the lines).

Now there are a number of ways to solve this. You can tell (because of the "x^2") that it is quadratic. So let's get it equal to zero:

0 = x^2 + 5x - 50

Now you can factor it, use your quadratic formula, or (if you hated yourself) do it as a completing the square problem. I'm going to factor.

I can see from going through a list in my head that the factors 10 and -5 multiply to -50 and add to 5, so I know that

0 = x^2 + 5x - 50 = (x + 10)(x - 5)

And so you know that x = -10 or 5.

Well, you know the parking lot cannot be -10 yd long. So we must say that W = x = 5, and, since L = W + 5, then L = 5+5 = 10. So your width is 5 yd and length is 10 yd.

<h2>mark me brainlist</h2>
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