A family has an annual income of $30,600 Of this, 1/4 is spent for food, 1/5 for housing, 1/10 for clothing, 1/9 for savin
1 answer:
Answer:
$6,120
Step-by-step explanation:
1/5 (one-fifth) of the family's annual income ($30,600) is spent on housing- as the word problem states.
You have to find 1/5 (one-fifth) of* $30,600.
Write it out as an equation.
*The <em>of</em><em> </em>in the word equation (1/5 of 30600) simply means multiplication.
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Using the z-distribution, the 99% confidence interval to estimate the population proportion is: (0.2364, 0.4836).
<h3>What is a confidence interval of proportions?</h3>A confidence interval of proportions is given by:
In which:
is the sample proportion.
- z is the critical value.
- n is the sample size.
In this problem, we have a 99% confidence level, hence, z is the value of Z that has a p-value of
, so the critical value is z = 2.575.
The estimate and the sample size are given by:
.
Then the bounds of the interval are:
The 99% confidence interval to estimate the population proportion is: (0.2364, 0.4836).
More can be learned about the z-distribution at brainly.com/question/25890103
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Answer:
The value of x is 3/2.
Step-by-step explanation:
Given data in the question:-
We have to find the value x.
Let be eq(i).
Solving eq (i)
using the properties of the exponents we have
if aⁿ=aˣ
then n=x
Hence the answer is 3/2.