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gulaghasi [49]
3 years ago
11

|(-127) +224|+|-130+(-140) |​

Mathematics
1 answer:
o-na [289]3 years ago
6 0

Answer:

|(-127) +224|+|-130+(-140) |​

| 97| + |-270|

97 + 270

367

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Identify the inequality that represents the following problem
ValentinkaMS [17]

Answer:

3n + 2 \geqslant 8

Step-by-step explanation:

2 more than 3 time mean 3n+2

"is atleast 8" means it can be 8 or more so c. is right answer

5 0
3 years ago
The cost of a unit is made up of $6.25 material cost, $4.75 labour cost, and $3.25 overhead. What is the ratio that exists betwe
blsea [12.9K]

Answer:

The ratio that exist between this three elements are 25 : 19 : 13.

Step-by-step explanation:

Ratio compares one thing to another. Ratios indicate the comparison of the size of a number to another . One trick about ratio is that you can multiply or divide the ratios by same number. For example the ratio of boy to girls can be represented as 3 : 4. If you multiply the ratios by 2 you will get the ratio 6 : 8 and it still represent the same ratios of boys to girls. Ratios can be written as a fraction for example 3/4 for our example.

The cost of the unit is made up of $6.25 , $4.75 and $3.25.

$6.25  $4.75  $3.25 . Let us multiply by 100 to remove the decimals.

625 : 475 : 325 . Now let simplify the ratios by dividing through by 25.

625/25 : 475/25 : 325/25 . The simplest ratios can be written as follows

The ratios are 25 : 19 : 13.

6 0
3 years ago
The dye dilution method is used to measure cardiac output with 3 mg of dye. The dye concentrations, in mg/L, are modeled by c(t)
Lemur [1.5K]

Answer:

Cardiac output:F=0.055 L\s

Step-by-step explanation:

Given : The dye dilution method is used to measure cardiac output with 3 mg of dye.

To Find : Find the cardiac output.

Solution:

Formula of cardiac output:F=\frac{A}{\int\limits^T_0 {c(t)} \, dt} ---1

A = 3 mg

\int\limits^T_0 {c(t)} \, dt =\int\limits^{10}_0 {20te^{-0.06t}} \, dt

Do, integration by parts

[\int{20te^{-0.6t}} \, dt]^{10}_0=[20t\int{e^{-0.6t} \,dt}-\int[\frac{d[20t]}{dt}\int {e^{-0.6t} \, dt]dt]^{10}_0

[\int{20te^{-0.6t}} \, dt]^{10}_0=[\frac{-20te^{-0.6t}}{0.6}+\frac{20}{0.6}\int {e^{-0.6t} \,dt]^{10}_0

[\int{20te^{-0.6t}} \, dt]^{10}_0=[\frac{-20te^{-0.6t}}{0.6}+\frac{20e^{-0.6t}}{(0.6)^2}]^{10}_{0}

[\int{20te^{-0.6t}} \, dt]^{10}_0=[\frac{-200e^{-6}}{0.6}+\frac{20e^{-6}}{(0.6)^2}]+\frac{20}{(0.60^2}

[\int{20te^{-0.6t}} \, dt]^{10}_0=\frac{20(1-e^{-6}}{(0.6)^2}-\frac{200e^{-6}}{0.6}

[\int{20te^{-0.6t}} \, dt]^{10}_0\sim {54.49}

Substitute the value in 1

Cardiac output:F=\frac{3}{54.49}

Cardiac output:F=0.055 L\s

Hence Cardiac output:F=0.055 L\s

4 0
3 years ago
Find the length of base PQ in the trapezoid.
iris [78.8K]

Answer:

PQ = 20

Step-by-step explanation:

Theorem:  The length of the median of a trapezoid is the average of the base lengths.

\frac{PQ + 12}{2}  = 16

PQ + 12 = 32

PQ = 20

See how easy that is if you know the theorem!

5 0
3 years ago
Mishka is on a long road trip, and she averages 75 mph for 2 hours while she's driving on the highway. While she's driving on si
slega [8]

If she goes 75 mph for 2 hours, that's 150 miles altogether. 45 mph for 1 hour is 45 miles, so 150 + 45 is 195 miles.

8 0
3 years ago
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