<span>Center(0,0)
a^2=16
a=4
b^2=9
b=3
c^2=a^2+b^2=16+9=25
c=√25=5</span>
Answer:
2.5*10^7 thank you
Step-by-step explanation:
thank you
Answer:
X= 8
Y= 130
(8, 130)
Step-by-step explanation:
I used a graphing calculator to see where the two equations intersected.
Hope this helped :)
Since the second equation gives a value for a, we can substitute it into the other equation to find a value for B.
Let's substitute b-2 into the first equation wherever there is an a.
a - 3b = 4
(b-2) - 3b = 4
b - 2 - 3b = 4
-2 - 2b = 4
-2b = 6
b = -3
Now let's find a by substituting -3 into either of the equations to find the value of a.
a = b - 2
a = -3 - 2
a = -5
So your solution set is (-5, -3)
Answer:
What are the options?
Step-by-step explanation:
