Answer:
The degrees of freedom are given by:
The significance level is 
and then the critical value can be founded in th chi square table we need a quantile that accumulates 0.05 of the area in the right tail of the distribution and for this case is:
And if the chi square statistic is higher than the critical value we can reject the null hypothesis in favor of the alternative.
Step-by-step explanation:
We have the followign system of hypothesis:
Null hypothesis: 
Alternative hypothesis: 
The degrees of freedom are given by:
The significance level is and then the critical value can be founded in th chi square table we need a quantile that accumulates 0.05 of the area in the right tail of the distribution and for this case is:
And if the chi square statistic is higher than the critical value we can reject the null hypothesis in favor of the alternative.
Answer:
k = 3
Step-by-step explanation:
Given
f(x) = 0.5x
g(x) = 0.5x - k
Required
Find k
<em>The question illustrates changing of positions of lines along the x and/or y axis;</em>
<em>But in this case; if graph f(x) is shifted down, then it represents a negative shift of points in the y axis.</em>
Given that f(x) = 0.5x
and f(x) is shifted down by 3 units to give g(x); then:
f(x) - 3 = g(x)
Substitute 0.5x for f(x)
0.5x - 3 = g(x)
Recall that g(x) = 0.5x - k ---------- (given)
0.5x - 3 = 0.5x - k
Subtract 0.5x from both sides
-0.5x + 0.5x - 3 = -0.5x + 0.5x - k
-3 = -k
Multiply both sides by -1
-3 * -1 = -k * -1
3 = k
k = 3
<em>Hence, the value of k is 3</em>
To answer the problem above, divide the numerical portion and the exponential portion of the given numbers. 4.5 divided by 9 is 0.5. Furthermore, 10^3 divided by 10^7 is 10^-4. The answer is
0.5 x 10^-4
This may still be written in a standard form,
5 x 10^-5
Thus, the answer is <em>5 x 10^-5</em>.
Subtract 20n from both sides of the equation.
n^2+100-20n=0
factor using the perfect square rule.
(n-10)^2=0
set the n-10 equal to 0.
n-10=0
add 10 to both sides of the equation.
n=0
Answer:
D.
Step-by-step explanation:
The answer is D) -25n-2
