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Mathematics

2 answers:

Juliette [100K]3 years ago

6 0

Answer:

x1 = -8 and x2 = 9?

Alja [10]3 years ago

6 0

= x - 8 / x = 2 / x + 9

= Let's solve your equation step-by-step.

= x − 8x = 2x + 9

= x + − 8x = 2x + 9

Multiply all terms by x and cancel:

xx + −8 = 2 + 9x

x² −8 = 9x + 2 ( Simplify both sides of the equation )

x² − 8 − (9x + 2) = 9x + 2 − (9x + 2) (Subtract 9x+2 from both sides)

x² − 9x − 10 = 0

( x + 1 )( x − 10 ) = 0 (Factor left side of equation)

x +1 = 0 or x − 10 = 0 (Set factors equal to 0)

x = − 1 or x = 10

Check answers. (Plug them in to make sure they work.)

<h3>x= −1 ( Works in original equation )</h3><h3>x = 10 ( Works in original equation )</h3><h3 />

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4vir4ik [10]

<u>Answer:</u>

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<u>Step-by-step explanation:</u>

$\frac { 4 } { x - 4 } = \frac { x } { x - 4 } - \frac { 4 } { 3 } \\ \frac { 4 } { x - 4 } - \frac { x } { x - 4 } = - \frac { 4 } { 3 } \\ \frac { 4 - x } { x - 4 } = - \frac { 4 } { 3 } \\ 3 ( 4 - x ) = - 4 ( x - 4 ) \\ 1 2 - 3 x = - 4 x + 1 6 \\ 4 x - 3 x = 1 6 - 1 2 \\ x = 4 \\$

This solution is extraneous. Reason being that even if it can be solved algebraically, it is still not a valid solution because if we substitute back $x=4$ , we will get two fractions with zero denominator which would be undefined.