Multiply the first fraction by two and the second by twenty five on both top and bottom.
16/50 + 25/50 = 41/50
<span>find the equations of the lines in slope-intercept form which is y=mx+b where m=slope b=y intercept
the choices:
0 solutions: means the lines don't intercect at all, meaning same slope but different y intercept or they ar paralell
1 solution: lines intercect in 1 point
2 solutions: curvy line with a straight line thorugh middle
infinetly solutions: same line
to find slope you do
slope=(y1-y2)/(x1-x2)
first line is
(-4,8)
(4,6)
(x,y)
x1=-4
y1=8
x2=4
y2=6
subsitute
(8-6)/(-4-4)=2/-8=-1/4
slope=-1/4
subsitute
y=-1/4x+b
subsitute one of the points
(4,6)
x=4
y=6
6=-1/4(4)+b
6=-1+b
add 1 to both sides
7=b
y=-1/4+7
now solve for the other equation
(-1,1)
(3,5)
x1=-1
y1=1
x2=3
y2=5
subsitute
(1-5)/(-1-3)=(-4)/(-4)=4/4=1
y=1x+b
subsitute
(-1,1)
x=-1
y=1
1=1(-1)+b
1=-1+b
add 1
2=b
y=x+2
we have the lines
y=-1/4x+7 and
y=x+2
solve for a common solution
y=x+2 and y=-1/4x+7 therefor
x+2=-1/4x+7
subtract 7 from both sides
x-5=-1/4x
mulitply both sides by -4
-4x+20=x
add 4x to both sides
20=5x
divide both sides by 5
4=x
subsitute
y=x+2
y=4+2
y=6
the soluiton is (4,6)
there is only one solution
the answer is B</span>
Answer: No, x+3 is not a factor of 2x^2-2x-12
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Explanation:
Let p(x) = 2x^2 - 2x - 12
If we divide p(x) over (x-k), then the remainder is p(k). I'm using the remainder theorem. A special case of the remainder theorem is that if p(k) = 0, then x-k is a factor of p(x).
Compare x+3 = x-(-3) to x-k to find that k = -3.
Plug x = -3 into the function
p(x) = 2x^2 - 2x - 12
p(-3) = 2(-3)^2 - 2(-3) - 12
p(-3) = 12
We don't get 0 as a result so x+3 is not a factor of p(x) = 2x^2 - 2x - 12
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Let's see what happens when we factor p(x)
2x^2 - 2x - 12
2(x^2 - x - 6)
2(x - 3)(x + 2)
The factors here are 2, x-3 and x+2
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