D^2 + 2d - 8 = 0
explain plz
1 answer:
Answer:
d^2 +2d-8=0
first pick two numbers which add up to make +2 and by multiplying those two numbers they should be able to create -8.
so for example 4 and 2
4-2=2
4 x -2= -8
so now factorise:
d^2 +2d-8=0
d^2+4d-2d -8=0
d(d+4)-2(d+4)=0
d+4=0 d-2=0
d=-4 d=2
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