We' supposed to indicate which statement is true/false.
Note that, if a sample size is 40 or over, we can use the t distribution even with skewed data. So it's not highly sensitive to non-normality of the population from which samples are taken. So statement A is false.
It's true that the t-distribution assumes that the population from which samples are drawn is normally distributed. So B is true.
For skewed data or with extreme outliers, we can't use the t distribution. We only use t distribution as long as we believe that the population from which samples are drawn is closed to a bell-shape. So C is true.
Lastly, statement D is against statement C. So D is false.
Answer:
we don't have the full answer sry.
Step-by-step explanation:
Answer:
25 and 54
Step-by-step explanation:
(a)
6z² - 2z + 5 ← substitute z = 2
= 6(2)² - 2(2) + 5
= 6(4) - 4 + 5
= 24 - 4 + 5
= 20 + 5
= 25
(b)
64 - 5z ← substitute z = 2
= 64 - 5(2)
= 64 - 10
= 54
Answer:
180
Step-by-step explanation:
add 1% to 31.50 to get 31.815
then take the total 5276.70 and divide by 31.815
