Answer:
since this is a parallelogram meaning the sides are equal then JE would equal the same as GJ so that is 15
Step-by-step explanation:
Which one is question 20??
Let the total no. of 25 p coins be x
50p coins = 2x
Value of 25 p coins ( in rupees) = 0.25*x =0.25x
Value of 50p coins ( in rupees) = 0.5*2x = x
0.25x+x = 25
1.25x =25
x = 25/1.25 = 20
no. if 25p coins = 20
and 50p coins = 2*20 = 40
If the whole diameter of sphere is 6 inch(means radius is 3 inch) & thickness of material is 1 inch, so the radius of the hollow part should be 2 inch (3-1=2)
The total volume of the ball will be;
= Total volume - Volume of hollow part
= 4/3πr³ - 4/3πr³
= 4/3 × 3.14 × (3)³ - 4/3×3.14×(2)³
= 4 × 3.14 × 9 - 4/3 × 3.14 × 8
= 113.04 - 33.52
= 79.52
If the density of the material is 3.25 g/in3, then the density of 79.52 inch³ should be;
= 79.52 × 3.25
= 258.44 g
Now, if there are 8 spheres in one box, the weight if box will be;
= 258.44 × 8
= 2,067.52 g
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Ahh! Finally done with this, if you have any doubt just do ask me :)
Answer:
28y^3 -35y^5
Step-by-step explanation:
= 7y^3(4) -7y^3(5y^2)
= 28y^3 -35y^5
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The applicable rule of exponents is ...
(y^a)(y^b) = y^(a+b)
