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tangare [24]
3 years ago
14

The area of a square is decreasing at a rate of 43 square inches per second. At the time when the side length of the square is 7

, what is the rate of change of the perimeter of the square? Round your answer to three decimal places (if necessary).
Mathematics
1 answer:
Sergio039 [100]3 years ago
8 0

Answer:

26.230 Inches per second.

Step-by-step explanation:

Since, Area of square is decreasing at the rate of 43 square inches per second And area is directly proportional to square of the side , So

Its side will be decreasing at the rate of \sqrt{43} inches per second .

Now,

Perimeter of square is directly proportional to 4 times of the side of the square.

so Perimeter of square will be decreasing at the rate of 4× \sqrt{43}

After rounding off to three decimal places we will get 26.230 Inches per second.

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skelet666 [1.2K]
Data:

<span>segment AU = 20x + 108,
segment UB = 273,
segment BC = 703,
segment UV = 444,
segment AV = 372 and
segment AC = 589.

From the figure:

1) Similarity => segment AB / segment BC = segment AU / segment UV

2) segment AB = segment AU + segment UB = 20x + 108 + 273 = 20x + 381

=> (20x + 381) / 703 = (20x + 108) / 444

=> 444 (20x + 381) = 703 (20x + 108)

=> 8880x + 169164 = 14060x + 75924

=> 14060x - 8880x = 169164 - 75924

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Answer: x = 18
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Answer:

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