1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Harrizon [31]
3 years ago
9

Match each table with the equation that represents the same proportional relationship. Match each table with the equation that r

epresents the same proportional relationship.
Mathematics
1 answer:
Alisiya [41]3 years ago
7 0
29 tables of relationships is the answer to your equation above … THANK ME LATER
You might be interested in
PLEASE HELP ASAP!!!!​
Elodia [21]

Answer:

I think its D? I'm not sure sorry if I get it wrong

7 0
2 years ago
Read 2 more answers
I’ll give the Brainliest!!!
Varvara68 [4.7K]
It’s B hope this helps
7 0
3 years ago
Help me please I am begging y’all
cupoosta [38]
2 is the answer i think
7 0
3 years ago
One household is to be selected at random from a town. ​ ​The probability that ​the household has a cat is 0.20.2 . ​ ​The proba
dimulka [17.4K]

Answer:

There is a 50% probability that the household has a dog, given that the household has a ​cat.

Step-by-step explanation:

We solve this problem building the Venn's diagram of these probabilities.

I am going to say that:

A is the probability that a household has a cat.

B is the probability that a household has a dog.

We have that:

A = a + (A \cap B)

In which a is the probability that a household has a cat but not a dog and A \cap B is the probability that a household has both a cat and a dog.

By the same logic, we have that:

B = b + (A \cap B)

The probability that the household has a cat or a dog is 0.5

a + b + (A \cap B) = 0.5

The probability that the household has a dog ​is 0.4

B = 0.4

B = b + (A \cap B)

b = 0.4 - (A \cap B)

The probability that ​the household has a cat is 0.2.

A = 0.2

A = a + (A \cap B)

a = 0.2 - (A \cap B)

So

a + b + (A \cap B) = 0.5

0.2 - (A \cap B) + 0.4 - (A \cap B) + (A \cap B) = 0.5

A \cap B = 0.1

What is ​the probability that the household has a dog, given that the household has a ​cat?

20% of the households have a cat, and 10% have both a cat and a dog. So

P = \frac{A \cap B}{A} = {0.1}{0.2} = 0.5

There is a 50% probability that the household has a dog, given that the household has a ​cat.

4 0
3 years ago
Given the following exponential function, identify whether the change represents growth or decay, and
cestrela7 [59]

Answer: 97% growth rate.

Step-by-step explanation:

Hi, to answer this question we have to analyze exponential function:

A = P (1 + r) t  

Where:

p = initial value

r = growth or decay rate (decimal form)

t= number of time intervals

A = value after t intervals

Replacing with the values given:

y=3400(1.97)^x

Where the term 1.97 = 1 + r

Solving for r:

1.97-1 = r

0.97 =r

Since the rate is positive, it is a  growth rate.

To determine the percentage we have to multiply it by 100

0.97 x 100 = 97%

Feel free to ask for more if needed or if you did not understand something.

6 0
3 years ago
Other questions:
  • In an aquarium, there are 6 large fish and 8 small fish. Half of the large fish are blue.
    14·2 answers
  • What is the total cost of $ 2.95 notebook plus 5 %
    6·1 answer
  • Find the area of a circle with a radius of 8. Either enter an exact answer in terms of π or use 3.14 for π and enter your answer
    10·1 answer
  • For the data in the table, tell whether y varies directly with x. If it does, write an equation for the direct variation.
    9·1 answer
  • What quadrant would -5,-8 be placed
    15·1 answer
  • Solve for y. ln(y-1)-ln2=x+ln x
    8·1 answer
  • 5,832, _, 648, 216, 72, _,8
    7·2 answers
  • Need answer!! please help.
    8·1 answer
  • Please help with these 2 questions :(( I really will appreciate it a lot
    15·1 answer
  • Can someone help me with this please​
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!