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nexus9112 [7]
4 years ago
9

Solve 8w – 3r = 45 for r

Mathematics
1 answer:
bogdanovich [222]4 years ago
7 0
<span>8w – 3r = 45 
3r = 8w - 45
  r = 8w/3 - 15
hope it helps</span>
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Find the interest rate r compounded monthly if the principal P = $4,300 reaches the future value F = $4,720 in t = 6 years. Roun
kirza4 [7]

Answer:

  1.55%

Step-by-step explanation:

Fill in the values and solve for the rate using the future value formula.

  FV = P(1 +r/n)^(nt)

  4720 = 4300(1 +r/12)^(12·6)

  (4720/4300)^(1/72) = 1 +r/12

  r = 12(4720/4300)^(1/72) -1) ≈ 0.015542

The annual interest rate is about 1.55%.

4 0
3 years ago
Assume that a simple random sample has been selected from a normally distributed population. State the hypotheses, find the test
BaLLatris [955]

Solution

Hypotheses:

- The population mean is 132. In order to test the claim that the mean is 132, we should check for if the mean is not 132.

- Thus, the Hypotheses are:

\begin{gathered} H_0:\mu=132 \\ H_1:\mu\ne132 \end{gathered}

Test statistic:

- The test statistic has to be a t-statistic because the sample size (n) is less than 30.

- The formula for finding the t-statistic is:

\begin{gathered} t=\frac{\bar{X}-\mu}{\frac{s}{\sqrt{n}}} \\  \\ where, \\ \bar{X}=\text{ Sample mean} \\ \mu=\text{ Population mean} \\ s=\text{ Standard deviation} \\ n=\text{ Sample size} \end{gathered}

- Applying the formula, we have:

\begin{gathered} t=\frac{137-132}{\frac{14.2}{\sqrt{20}}} \\  \\ t=\frac{5}{3.1752} \\  \\ t\approx1.5747 \end{gathered}

Critical value:

- The critical value t-critical, is gotten by reading off the t-distribution table.

- For this, we need the degrees of freedom (df) which is gotten by the formula:

\begin{gathered} df=n-1 \\ df=20-1=19 \end{gathered}

- And then we also use the significance level of 0.1 and the fact that it is a two-tailed test to trace out the t-critical. (Note: significance level of 0.1 implies 10% significance level)

- This is done below:

- The critical value is 1.729

P-value:

- To find the p-value, we simply check the table for where the t-statistic falls.

- The t-statistic given is 1.5747. We simply check which values this falls between in the t-distribution table. It falls between 1.328 and 1.729. We can simply choose a value between 0.1 and 0.05 and multiply the result by 2 since it is a two-tailed test.

- However, we can also use a t-distribution calculator, we have:

- Thus, the p-value is 0.13183

Final Conclusion:

- The p-value is 0.13183, and comparing this to the significance level of 0.1, we can see that 0.13183 is outside the rejection region.

- Thus, the result is not significant and we fail to reject the null hypothesis

7 0
2 years ago
What is 67 divided by 6 and what is the remainder
ahrayia [7]
6 x 11= 66
67 - 66 = 1

67/6 = 11 
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7 0
3 years ago
Read 2 more answers
3/5 - 2/5 please help
Oduvanchick [21]
3/5 - 2/5 = 1/5

I hope that helps!
8 0
3 years ago
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What is the first and second derivative of xe^(2x)?
Nimfa-mama [501]
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5 0
3 years ago
Read 2 more answers
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