<span>1. First, label the axis on your graph, with units:
time on the x-axis, in units of hours;
distance on the y-axis, in units of miles.
2. Draw a graph of distance vs. time. Distance after the first hour = 69 miles, distance after the 2nd hour = 138 miles, etc.
3. Observe that this graph is a STRAIGHT LINE with constant slope. Therefore the relationship is PROPORTIONAL.
For every other kind of graph -- i.e. not a straight line -- the relationship is NON-PROPORTIONAL.
Hope this helps. </span>
Hi there....
-8f > 56
Divide both sides by -8
-8f/-8 > 56/-8
f < -7
The correct option is : B
The answer is 3.14 m
The area (A) of the circle with radius r is: A = π · r²
The area of the quarter of the circle is: A1 = 1/4A = 1/4 · π · r²
We have:
A1 = ?
r = ?
π = 3.14
d = 4 m
A diameter d is the twice of the radius r: d = 2r.
Therefore, the radius is the half of the diameter: r = d/2
So, the area of the quarter circle would be:
A1 = 1/4 · π · r² = 1/4 · π · (d/2)² =1/4 · π · d²/2² = 1/4 · π · d²/4 = 1/16 · π · d²
A1 = 1/16 · π · d² = 1/16 · 3.14 · 4² = 1/16 · 3.14 · 16 = 3.14 m
There isn't a picture so I can't see the model to help you.
Let h(t) represent the height of the projectile after t seconds. If the projectile is being launched from the ground, then h(0)=0, and h(t)=-4.9t²+98t. When the equation is in this form, the maximum height is determined by -98/2(-4.9), or after 10 seconds. Thus
-4.9(100)+98(10)=490 m as the highest point of the projectile
Then, when it hits the ground, h(t)=0, so
0=-4.9t²+98t
98t=4.9t²
4.9t=98
t=20
☺☺☺☺
