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Slav-nsk [51]
3 years ago
8

The linear​ model, y equals . 1967 x plus 15.66 comma provides the approximate​ enrollment, in​ millions, between the years 2003

and​ 2012, where x equals 0 corresponds to​ 2003, x equals 1 to​ 2004, and so​ on, and y is in millions of students.
Mathematics
1 answer:
Veseljchak [2.6K]3 years ago
3 0

Answer:

The number of students enrolled in 2012 is approximately 17,400,000 to the nearest 100,000

Step-by-step explanation:

y = 0.1967x + 15.66

x = years since 2003

y = number of students enrolled in millions

In 2012, x = 9 (2012 is 9 years from 2003)

y = 0.1967(9) + 15.66

y = 1.7703 + 15.66 = 17.4303 millions = 17,430,300 = 17,400,000 to the nearest 100,000

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Step-by-step explanation:

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4) Solve and no matter what points you’ll get -7/4

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3 years ago
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Sunny_sXe [5.5K]

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8 0
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83 Tee (CsT Sequences and Functions
NISA [10]

Answer:

The common difference is same = d = -9

Therefore, the data represent a linear function.

Step-by-step explanation:

Given the table

x                        y

1                         4

2                        -5

3                        -14

4                        -23

5                         -32

Finding the common difference between all the adjacent terms of y-values

d = -5 - 4 = -6,

d = -14 - (-5) = -14+5 = -9

d = -23 - (-14) = -23 + 14 = -9

d = -32 - (-23) = -32 + 23 = -9

It is clear that the common difference between all the adjacent terms is same.

Thus,

d = -9

We know that when y varies directly with x, the function is a linear function.

Here, it is clear that each x value varies 1 unit, and each y value varies -9 units.

i.e. The common difference is same = d = -9

Therefore, the data represent a linear function.

3 0
2 years ago
If f(x) = x-6 and g(x)= 1/2x (x+3), find g(x) * f(x)
sertanlavr [38]

Answer:

Final answer is g\left(x\right)\cdot f\left(x\right)=\frac{\left(x-6\right)}{2x\left(x+3\right)}.

Step-by-step explanation:

given functions are f(x)=x-6 and g\left(x\right)=\frac{1}{2x\left(x+3\right)}.

Now we need to find about what is the value of g\left(x\right)*f\left(x\right).

g\left(x\right)*f\left(x\right) simply means we need to multiply the value of  f(x)=x-6 and g\left(x\right)=\frac{1}{2x\left(x+3\right)}.

g\left(x\right)\cdot f\left(x\right)=\frac{1}{2x\left(x+3\right)}\cdot\left(x-6\right)

g\left(x\right)\cdot f\left(x\right)=\frac{\left(x-6\right)}{2x\left(x+3\right)}

Hence final answer is g\left(x\right)\cdot f\left(x\right)=\frac{\left(x-6\right)}{2x\left(x+3\right)}.

5 0
3 years ago
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alexdok [17]
All Togther they bought 37 quarts of iced tea
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