All categories

3 years ago

Which expression represents the total surface area, in square centimeters, of the square pyramid?

Mathematics

2 answers:

Anit [1.1K]3 years ago

5 0

Answer:

Total area = (8.2)(8.2) + 4[1/2(8.2) (10.3)]

Step-by-step explanation:

From figure we can see a square pyramid with base edge 8.2 and slant height 10.3

Points to remember

Total area of square pyramid = Base area + Lateral face area

Lateral face area = 4 * One face area

<u>To find the lateral face area</u>

The face is like a triangle with base 8.2 and slant height = 10.3

Area of triangle = bh/2

Face area = 1/2(8.2) (10.3)

Lateral surface area = 4[1/2(8.2) (10.3)]

To find the base are

Base is a square with base edge = 8.2

Base area = side * side = (8.2)(8.2)

<u>To find the total area of pyramid</u>

Total area = Base area + Lateral face area

Total area = (8.2)(8.2) + 4[1/2(8.2) (10.3)]

Therefore the correct answer is first option

elena-14-01-66 [18.8K]3 years ago

4 0

Answer:

(8.2)(8.2) + 4[1/2(8.2) (10.3)]

Step-by-step explanation:

a. i tooke

You might be interested in

Flag question

xz_007 [3.2K]

Answer:

b. cosx + 6 sinx

Step-by-step explanation:

$\frac{d}{dx} ( sinx - 6 cos \: x) \\ \\ = \frac{d}{dx} sinx - 6\frac{d}{dx} cos \: x \\ \\ = cos \: x - 6( - sin \: x) \\ \\ = cos \: x + 6 \: sin \: x$

7 0

2 years ago

Read 2 more answers

Write 2 times 5 + (5+8)+ (8 times 2) as the product of two factors

marysya [2.9K]

Answer: 3 and 13 the solution to the equation is 39

Step-by-step explanation:

3 0

2 years ago

Use differentials to estimate the amount of metal in a closed cylindrical can that is 26 cm high and 10 cm in diameter if the me

Afina-wow [57]

Answer:

The estimated amount of metal in the can is 87.96 cubic cm

Step-by-step explanation:

We can find the differential of volume from the volume of a cylinder equation given by

$V= \pi r^2 h$

Thus that way we will find the amount of metal that makes up the can.

Finding the differential.

A small change in volume is given by:

$dV =\cfrac{\partial V}{\partial h} dh + \cfrac{\partial V}{\partial r} dr$

So finding the partial derivatives we get

$dV =\pi r^2 dh + \pi 2r h dr$

$dV =\pi r^2 dh + 2\pi r h dr$

Evaluating the differential at the given information.

The height of the can is h = 26 cm, the diameter is 10 cm, which means the radius is half of it, that is r = 5 cm.

On the other hand the thickness of the side is 0.05 cm that represents dr = 0.05 cm, and the thickness on both top and bottom is 0.3 cm, thus dh = 0.3 cm +0.3 cm which give us 0.6 cm.

Replacing all those values on the differential we get

$dV =\pi 5^2 (0.6) + 2\pi (5) (26) (0.05)$