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Flura [38]
3 years ago
15

If a truck travels for 3 hours, how many miles will it travel? __ miles

Mathematics
2 answers:
mamaluj [8]3 years ago
8 0

Answer:

There is no speed. With the information that you have given us, it could be said that the truck could be traveling at any speed, and therefore, could have gone any distance. Please provide more details.

Masja [62]3 years ago
5 0

Answer:

You need to know the miles per hour they are going to find out this answer.

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Consider the points A(5, 3t+2, 2), B(1, 3t, 2), and C(1, 4t, 3). Find the angle ∠ABC given that the dot product of the vectors B
Vilka [71]

Answer:

66.42°

Step-by-step explanation:

<u>Given:</u>

A(5, 3t+2, 2)

B(1, 3t, 2)

C(1, 4t, 3)

BA • BC = 4

Step 1: Find t.

First we have to find vectors BA and BC. We do that by subtracting the coordinates of the initial point from the coordinates of the terminal point.

In vector BA B is the initial point and A is the terminal point.

BA = OA - OB = (5-1, 3t+2-3t, 2-2) = (4, 2, 0)

BC = OC - OB = (1-1, 4t-3t, 3-2) = (0, t, 1)

Now we can find t because we know that BA • BC = 4

BA • BC = 4

To find dot product we calculate the sum of the produts of the corresponding components.

BA • BC = (4)(0) + (2)(t) + (0)(1)

4 = (4)(0) + (2)(t) + (0)(1)

4 = 0 + 2t + 0

4 = 2t

2 = t

t = 2

Now we know that:

BA = (4, 2, 0)

BC = (0, 2, 1)

Step 2: Find the angle ∠ABC.

Dot product: a • b = |a| |b| cos(angle)

BA • BC = 4

|BA| |BC| cos(angle) = 4

To get magnitudes we square each compoment of the vector and sum them together. Then square root.

|BA| = \sqrt{4^2 + 2^2 + 0^2} = \sqrt{20} = 2\sqrt{5}

|BC| = \sqrt{0^2 + 2^2 + 1^2} = \sqrt{5}

2\sqrt{5}\sqrt{5}\cos{(m\angle{ABC})} = 4

10\cos{(m\angle{ABC})} = 4

\cos(m\angle{ABC}) = \frac{4}{10}=\frac{2}{5}

m\angle{ABC} = cos^{-1}{(\frac{2}{5})}

m\angle{ABC} = 66.4218^{\circ}

Rounded to two decimal places:

m\angle{ABC} = 66.42^\circ

3 0
2 years ago
Use the given equation to determine if the points in the brackets are on the graph
dmitriy555 [2]

The points in the brackets are on the graph are (0, 2) and (6, 10)

<h3>How to determine if the points in the brackets are on the graph?</h3>

The equation of the line is given as

4x - 3y = -6

The points are given as:

{(0,2),(1,3),(4,7),(6,10)}

Rewrite as

(x, y) = {(0,2),(1,3),(4,7),(6,10)}

Next, we substitute the x and y values in the equation 4x - 3y = -6

So, we have

(0, 2):

4(0) - 3(2) = -6

-6 = -6 ---- true

(1, 3):

4(1) - 3(3) = -6

-5 = -6 ---- false

(4, 7):

4(4) - 3(7) = -6

-5 = -6 ---- false

(6, 10):

4(6) - 3(10) = -6

-6 = -6 ---- true

Hence, the points in the brackets are on the graph are (0, 2) and (6, 10)

Read more about linear equations at:

brainly.com/question/2226590

#SPJ1

3 0
1 year ago
DUDE THIS IS MY LAST QUESTION PLEASE HELP
Alborosie

Answer:

B

Step-by-step explanation:

3 x -3 is -9

-2 x 4 is -8

-9 x -8 is 72

7 0
3 years ago
Read 2 more answers
Help please 6+6x4+8.................
Natasha_Volkova [10]
,12x12=144.................
6 0
3 years ago
Read 2 more answers
The expanded fom of (a-b)²​
emmainna [20.7K]

Answer:

Step-by-step explanation:

(a-b)^{2} = a^{2} - 2ab + b^{2}

Hope this helps

plz mark as brainliest!!!!!

4 0
3 years ago
Read 2 more answers
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