Let AB extended intersect DC extended at point E
<span>We now have right triangle BEC with E = 90 degrees </span>
<span>For triangle BEC: </span>
<span>Exterior angle at E = 90 </span>
<span>Exterior angle at C = 148 (given) </span>
<span>Exterior angle of all polygons add up to 360 degrees </span>
<span>Exterior angle at B = 360−148−90 = 122 </span>
<span>So in quadrilateral ABCD </span>
<span>B = 122 </span>
<span>D = 360−44−148−122 = 46</span>
4+1, 3+2, 2+3, 1+4. 4 total combinations, unless 4+1 and 1+4 are the same. In that case, there are only 2, 1+4, and 2+3
1. 4
2. 9
3. 21
are the answers
Formula to convert F to C:
(F -32) x 5/9
F = 63 + 10 = 73
73-32 = 41
41 x 5/9 = 22.77777
Rounded to the nearest degree = 23 C
We are given the equation y = 2(x – 3)^2 – 4 and is asked for the domain and range of the following function. In this case, there is no radical sign so the domain includes all real numbers. The range has a minimum value of -4 since the squaring makes the value on the first term positive. Hence the answer is A.
