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8090 [49]
3 years ago
7

If ST=19 and S lies at -4 , where could T be located?

Mathematics
1 answer:
Natasha2012 [34]3 years ago
8 0

Answer:

15 or -23

Step-by-step explanation:

I think you probably already turned this in but in case you haven't:

ST = 19 means that line segment ST is 19 units long. If we know that S is at -4, then T has to be 19 units away from -4, right?

So there's two directions we could go.

Add 19 to -4 to get 15, so T could be at 15. (If there's a line drawn between -4 and 15, it would be 19 units long.)

But the line could go left, towards negative infinity, too. So if we subtract 19 from -4, we'd get -23. T could also be at -23. (If there's a line drawn between -4 and -23, it would also be 19 units long. There's no such thing as a negative length.)

Please mark as Brainliest! :)

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the midpoint of kl is m(4.8, -7.8). one endpoint is l(0.6, -5.6). find the coordinates of the other endpoint k.
Vera_Pavlovna [14]
\bf ~~~~~~~~~~~~\textit{middle point of 2 points }\\\\
\begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
%  (a,b)
&k&(~ x &,& y~) 
%  (c,d)
&l&(~ 0.6 &,& -5.6~)
\end{array}\qquad
%   coordinates of midpoint 
\left(\cfrac{ x_2 +  x_1}{2}\quad ,\quad \cfrac{ y_2 +  y_1}{2} \right)

\bf \left( \cfrac{0.6+x}{2}~~,~~\cfrac{-5.6+y}{2} \right)~=~\stackrel{midpoint}{(4.8~,~-7.8)}\quad 
\begin{cases}
\cfrac{0.6+x}{2}=4.8\\\\
0.6+x=9.6\\
\boxed{x=9}\\
---------\\
\cfrac{-5.6+y}{2}=-7.8\\\\
-5.6+y=-15.6\\
\boxed{y=10}
\end{cases}
8 0
3 years ago
A contractor completed five-ninths of a job before a second contractor completed an additional one-third. What fraction of the j
Firlakuza [10]
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8 0
3 years ago
A line passes through tge points (1,-3) and (4,6) what is the zero of this line ?
Maru [420]

Answer:

<em>The zero of the line is (2,0)</em>

Step-by-step explanation:

The equation of a line passing through points (x1,y1) and (x2,y2) can be found as:

\displaystyle y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)

We are given the points (1,-3) and (4,6). Substituting:

\displaystyle y+3=\frac{6+3}{4-1}(x-1)

Operating:

\displaystyle y+3=\frac{9}{3}(x-1)

y+3=3(x-1)

The zero of this line can be found by making y=0 and solving for x:

0+3=3(x-1)

3=3x-3

Adding 3:

6=3x

Solving:

x = 2

The zero of the line is (2,0)

3 0
2 years ago
Solve the equation x^3 + 2x^2 - 11x -12 = 0
vagabundo [1.1K]

Answer: there are 4 solutions

x = -2

x = -1/2 = -0.500

x =(3-√5)/2= 0.382

x =(3+√5)/2= 2.618

Step-by-step explanation:

4 0
3 years ago
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Answer:

Gerald will need to conduct fewer trials because experimental and theoretical results in experiments with small

numbers of possible outcomes are the same.

3 0
3 years ago
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