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3 years ago

11

PLEASE HELP!

1 answer:

Tanya [424]3 years ago

6 0

Answer:

$R = 10.39^\circ$

Step-by-step explanation:

Since you have the lengths of all the sides, you can use sine, cosine, or tangent to find the answer. Let's use the tangent ratio.

For angle C, AB is the opposite leg, and BC is the adjacent leg.

$\tan C = \dfrac{opp}{adj}$

$\tan C = \dfrac{22}{120}$

$C = \tan^{-1} \dfrac{22}{120}$

$C = 10.39^\circ$

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if 42% of a crowd of 3850 at a football match were females, how many females attended the football game?

sweet [91]

Answer: 1617

Step-by-step explanation:

You would need to find 42% of 3850

Convert 42% into decimal:

42/100 = 0.42

Multiply:

0.42*3850

= 1617

Therefore, there were 1617 females that attended the game

7 0

3 years ago

Read 2 more answers

Car A travels 20 mph faster than Car B. In the same time that Car A travels 252 miles, Car B travels 196 miles. Find their speed

RoseWind [281]

<u>Answer:</u>

A = 70

B = 90

<u>Step-by-step explanation:</u>

We know that Car A travels 20 mph faster than Car B.

Assuming the speed of Car B to be x and the speed of Car A to be x+20, we can write:

$\frac{196}{x} =\frac{252}{x+20}$

Taking the reciprocal of both sides to make x the subject:

$196(x+20)=252x$

$196x+3920=252x$

$252x-196x=3920$

$56x=3920$

$x=70$ ---> speed of Car A

Finding the speed of Car B: $x+20 = 70+20=90$

Therefore, the speed of Car A = 70 and the speed of Car B = 90.

8 0

3 years ago

Does anyone know how to change their username for Brainly????? If so HELP!!!!!!!!!! Will give 20 points to anyone I really don't

Len [333]

Answer:

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3 years ago

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50+51+52+...+101=...<br>Can you help me? I do not understand

Dmitriy789 [7]

Suppose

$S=50+51+52+\cdots+100+101$

At the same time, we can write

$S^*=101+100+99+\cdots+51+50$

Note that $S=S^*$ (just reverse the sum). Let's pair the first terms of $S$ and $S^*$ , and the second, and the third, and so on:

$S+S^*=(50+101)+(51+100)+(52+99)+\cdots+(100+51)+(101+50)$

Now, each grouped term in the sum on the right side adds to 151. There are 52 grouped terms on that same side (because there are 50 numbers in the range of integers 51-100, plus 50 and 101), which menas

$S+S^*=52\cdot151$

But $S=S^*$ , as we pointed out, so

$2S=52\cdot151\implies S=\dfrac{52\cdot151}2=3926$

5 0

3 years ago

PLZ HELP ASAP!!!!!!!!!!!!!!!!!!!!!!

nika2105 [10]

2. A
4. D
I don't know the rest but good luck.

4 0

3 years ago