A line is perpendiculat to another which has a slope of m if the perpendicular line has a slope of -1/m.
That means that if the product of slopes of two lines is -1, the two lines are perpendicular.
Here, y1=-7/4x, or m=-7/4
The perpendicular should have a slope of -1/m=-1/(-7/4)=4/7
Answer:
The given system has NO SOLUTION.
Step-by-step explanation:
Here, the given system of equation is:
6 x - 2 y = 5 .......... (1)
3 x - y = 10 .... (2)
Multiply equation 2 with (-2), we get:
3 x - y = 10 ( x -2)
⇒ - 6 x + 2 y = - 20
Now, ADD this to equation (1) , we get:
6 x - 2 y - 6 x + 2 y = 5 - 20
or, 0 = - 15
WHICH IS NOT POSSIBLE as 0 ≠ -15
Hence, the given system has NO SOLUTION.
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Answer:
70*20=1400/2= 700. that's all
The answer is option c (-1,0)
Solving the equation you get that the zeros of this are approximately
x ≈ -2.8019
x ≈ -1.4450
x ≈ 0.24698
Then the function has three real roots, but none of them is within the range (-1,0)
Below is a graph of the function.