The volume of the trough is V(w) = w³ + 20w² - 429w and the rate of change of the volume over a width of 38 inches to 53 inches is 4695 in³/in
<h3>What is an
equation?</h3>
An equation is an expression that shows the relationship between two or more variables and numbers.
Let w represent the width, hence:
length = w + 33, height = w - 13
Volume (V) = w(w + 33)(w - 13) = w³ + 20w² - 429w
V(w) = w³ + 20w² - 429w
Rate of change = dV/dw = 3w² + 40w - 429
When w = 38, dV/dw = 3(38)² + 40(38) - 429 = 5423
When w = 53, dV/dw = 3(53)² + 40(53) - 429 = 10118
Rate = 10118 - 5423 = 4695 in³/in
The volume of the trough is V(w) = w³ + 20w² - 429w and the rate of change of the volume over a width of 38 inches to 53 inches is 4695 in³/in
Find out more on equation at: brainly.com/question/2972832
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Answer:
k= 9
Step-by-step explanation:
hope this helps you
Answer:
confusion?
Step-by-step explanation:
your welcome
<h2>Hey there! </h2><h2>
</h2><h3>DIVIDE by
on BOTH SIDES </h3><h3>
</h3><h3>CANCEL out:
because it gives you
</h3><h3>KEEP:
because it helps us solve the number that is being
to
</h3><h3>
</h3><h2>Good luck on your assignment and enjoy your day! </h2><h2>~
</h2><h3 />
Answer:
1/20
Step-by-step explanation:
The probability of any of the friends sitting on any of the seats is equal.
So the probability of Hamad sitting on the first seat = 1/5
As Hamad is sat on the first seat, there are now 4 available seats, so the probability of Riyadh sitting on the second seat = 1/4
Therefore, probability of Hamad sitting on the first seat AND Riyadh sitting on the second seat = 1/5 x 1/4 = 1/20
