The diameter of a circle measures 17 mm. What is the measure of its radius ?
1 answer:
You might be interested in
Answer:
(x - 11)² + y² = 25
Step-by-step explanation:
First find the center
O = ( (15 +7 / 2), (-3 + 3)/2 )
O = (11, 0)
Then find the radius squared
use the distance formula from the center to either end point of the diameter
r² = (15 - 11)² + (-3 - 0)²
r² = 16 + 9
r² = 25
Formula for circle
(x - h)² + (y - k)² = r²
(h, k) is the center = (11, 0)
The equation is
(x - 11)² + y² = 25
Answer:
(1) The possible outcomes are: X = {0, 1, 2, 3}.
(2) The number of times should Hartley spin a difference of 1 is 36.
(3) The number of times should Hartley spin a difference of 0 is 24.
Step-by-step explanation:
The number of sections on the spinner is 4 labelled as {1, 2, 3, 4}.
The total number of spins for each of the spinner is, <em>n</em> = 96.
(1)
The sample space of spinning both the spinners together are:
S = {(1, 1), (1, 2), (1, 3), (1, 4)
(2, 1), (2, 2), (2, 3), (2, 4)
(3, 1), (3, 2), (3, 3), (3, 4)
(4, 1), (4, 2), (4, 3), (4, 4)}
Total = 16.
The possible outcomes are:
X = {0, 1, 2, 3}.
(2)
The sample space with the difference 1 are:
S₁ = {(1, 2), (2, 1), (2, 3), (3, 2), (3, 4), (4, 3)}
n (S₁) = 6
The probability of the difference 1 is:
The spinners were spinner 96 times.
The expected number of times would Hartley spin a difference of 1 is:
Thus, the number of times should Hartley spin a difference of 1 is 36.
(3)
The sample space with the difference 0 are:
S₂ = {(1, 1), (2, 2), (3, 3), (4, 4)}
n (S₂) = 4
The probability of the difference 0 is:
The spinners were spinner 96 times.
The expected number of times would Hartley spin a difference of 0 is:
Thus, the number of times should Hartley spin a difference of 0 is 24.