For this case we have that the figure shown is composed of a cylinder and a cone.
We have that the volume of a cylinder is given by:
Where:
A: It's the radio
h: It's the height
Substituting the values:
On the other hand, the volume of a cone is given by:
Where:
A: It's the radio
h: It's the height
Substituting the values:
Then, the total volume is:
Taking 
, we have to:
Answer:
Option D
xy² = x · y · y
xz = x · z
LCM(xy², xz) = x · y · y · z = xy²z
Answer: t = 1.25j
Explanation:
5/4 = 1.25
So 5 is t and 4 is j
=> t/j = 1.25
=> t = 1.25j
Step-by-step explanation:
=
−
±
2
−
4
√
2
x=2a−b±b2−4ac
Once in standard form, identify a, b, and c from the original equation and plug them into the quadratic formula.
9
2
−
8
1
=
0
9x^{2}-81=0
9x2−81=0
=
9
a=
a=9
=
0
b={\color{#e8710a}{0}}
b=0
=
−
8
1
c={\color{#129eaf}{-81}}
c=−81
=
−
0
±
0
2
−
4
⋅
9
(
−
8
1
)
√
2
⋅
9
x=2⋅9−0±02−4⋅9(−81)
