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Travka [436]
2 years ago
15

Please helpp i need this doneee :((

Mathematics
1 answer:
egoroff_w [7]2 years ago
6 0

Answer:

w = \frac{5}{8}, v = \frac{21}{2}

Step-by-step explanation:

With given information, we have \frac{TR}{TQ} = \frac{TS}{TP}, so \frac{5}{13} = \frac{3w}{3w+3}, which gives us w=\frac{5}{8}. Meanwhile, we have \frac{TR}{TQ}=\frac{RS}{QP}, so \frac{5}{13}=\frac{10}{2v+5}, which gives us v = \frac{21}{2}.

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You take the numerator and divide that by the denominator
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2 years ago
PLEASE HELP!! Serious answers only please!!
klemol [59]

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Step-by-step explanation:

Use the distributive property to get rid of the brackets.

9i + 2*7 + 2*3i        Use the multiplication property to simplify the imaginary terms

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7 0
2 years ago
PLS HELP ASAP WILL MARK BRAINLIEST Determine whether each relation is a function. Explain your reasoning.
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3 0
2 years ago
In the isosceles △ABC m∠ACB=120° and AD is an altitude to leg BC . What is the distance from D to base AB , if CD=4cm?
snow_lady [41]

If ΔACB is an isosceles triangle, then ∠A ≅ ∠B and AC ≅ CB

Since ∠C = 120° and ∠A + ∠B + ∠C = 180°, then ∠A = 30° and ∠B = 30°

Next, look at ΔADB.  ∠A + ∠D + ∠B = 180°, so ∠A + 90° + 30° = 180° ⇒ ∠A = 30°

Now look at ΔADC.  Since ∠A = 30° in ΔACB, and ∠A = 60° in ΔADB, then ∠A = 30° in ΔADC <em>per angle addition postulate.</em>

Now that we have shown that ΔADB and ΔADC are 30-60-90 triangles, we can use that formula to calculate the side lengths.

CD = 4 cm (given) so AC = 2(4 cm) = 8 cm

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BD = 12 cm, so HD = \frac{12}{2}cm = 6 cm

Answer: 6 cm



8 0
3 years ago
Read 2 more answers
Can someone please help me with these two questions! :( ill mark u as brainlest
Maslowich

Answer:

1.A by SSS axiom

2.F as angle A is 62*

4 0
2 years ago
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