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Travka [436]
3 years ago
15

Please helpp i need this doneee :((

Mathematics
1 answer:
egoroff_w [7]3 years ago
6 0

Answer:

w = \frac{5}{8}, v = \frac{21}{2}

Step-by-step explanation:

With given information, we have \frac{TR}{TQ} = \frac{TS}{TP}, so \frac{5}{13} = \frac{3w}{3w+3}, which gives us w=\frac{5}{8}. Meanwhile, we have \frac{TR}{TQ}=\frac{RS}{QP}, so \frac{5}{13}=\frac{10}{2v+5}, which gives us v = \frac{21}{2}.

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Question 3 of 10
avanturin [10]
The correct answer is: Option 15.20

Explanation:
At the end of her last billing the amount = $760

The minimum monthly payment of Janet's card is 2%.

To find the monthly payment, we need to find the 2% of $760.

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$760 * 2 / 100 = $15.20 > $10
4 0
2 years ago
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The temperature at any random location in a kiln used in the manufacture of bricks is normally distributed with a mean of 1000 a
NeX [460]

Answer:

b. 2.28%.

Step-by-step explanation:

Mean temperatue (μ) = 1000°F

Standard Deviation (σ) = 50 °F

For any temperature value, X, the z-score is given by:

z=\frac{X-\mu}{\sigma}

For X= 900°F

z=\frac{900-1000}{50}\\z=-2.0

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7 0
3 years ago
The product of $7d^2-3d+g$ and $3d^2+hd-8$ is $21d^4-44d^3-35d^2+14d-16$. What is $g+h$?
galina1969 [7]
<h2>Answer:</h2><h2>g = 2  and h = -5</h2>

Step-by-step explanation:

To find the product with unknown values of variables, multiply the terms and equate the value to the given product.

(7d^{2} - 3d + g)(3d^{2} + hd - 8) = 21d^{4}  + 7hd^{3} - 56d^{2} - 9d^{3} - 3hd^{2} + 24d + 3gd^{2} + ghd - 8g

(7d^{2} - 3d + g)(3d^{2} + hd - 8)     = 21d^{4}  + (7h-9) d^{3} + (3g-56-3h)d^{2}  + (24+gh)d -8g   ... (1)

Comparing eq(1) to the product given in question,

-8g = -1

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24 + gh = 14, sub g =2,

24 + 2h = 14

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3 0
3 years ago
What is the fraction for 7.71
igomit [66]
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You divide by 1 but to do that, you must move the decimal so that there are only whole numbers, but if you move the decimal, then you have to do the same for 1 but you move it to the right instead of the left=771./100.
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ICE Princess25 [194]

Answer:

is obviously 8

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