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3 years ago

Give at least one way that terminal-digit and middle-digit numbering are alike and one way that they are different.

1 answer:

4 0

Terminal digit filing is a filing system that works by means of the last two numbers on files to consolidate them. While middle digit filling uses a tripartite number, using the first part of the number for the second sort, middle part for the initial sort, and the third portion for the final sort. One way they are similar is that the two evade working with large numbers and overpowers the difficulties of crowding at the end of the storage.

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I need help

zhenek [66]

Answer:

10 miles

Step-by-step explanation:

35/7 ?/2 2x35=70/7=10 butterfly cross multiply and divide

4 0

3 years ago

Read 2 more answers

A tattoo enthusiast website claims that :

KATRIN_1 [288]

Answer:

The probability that a person is a Millennial given that they have tattoos is 0.5069 (50.69%) or about 0.51 (51%).

Step-by-step explanation:

We have here a case where we need to use Bayes' Theorem and all conditional probabilities related. Roughly speaking, a conditional probability is a kind of probability where an event determines the occurrence of another event. Mathematically:

$\\ P(A|B) = \frac{P(A \cap B)}{P(B)}$

In the case of the Bayes' Theorem, we have also a conditional probability where one event is the sum of different probabilities.

We have a series of different probabilities that we have to distinguish one from the others:

The probability that a person has a tattoo assuming that is a Millennial is:

$\\ P(T|M) = 0.47$

The probability that a person has a tattoo assuming that is of Generation X is:

$\\ P(T|X) = 0.36$

The probability that a person has a tattoo assuming that is of Boomers is:

$\\ P(T|B) = 0.13$

The probability of being of Millennials is:

$\\ P(M) = 0.22$

The probability of being of Generation X is:

$\\ P(X) = 0.20$

The probability of being of Boomers is:

$\\ P(B) = 0.22$

Therefore, the probability of the event of having a tattoo P(T) is:

$\\ P(T) = P(T|M)*P(M) + P(T|X)*P(X) + P(T|B)*P(B)$

$\\ P(T) = 0.47*0.22 + 0.36*0.20 + 0.13*0.22$

$\\ P(T) = 0.204$

For non-independent events that happen at the same time, we can say that the probability of occurring simultaneously is:

$\\ P(M \cap T) = P(M|T)*P(T)$

$\\ P(T \cap M) = P(T|M)*P(M)$

But

$\\ P(M \cap T) = P(T \cap M)$

Then

$\\ P(M|T)*P(T) = P(T|M)*P(M)$

We are asked for the probability that a person is a Millennial given or assuming that they have tattoos or P(M | T). Solving the previous formula for the latter:

$\\ P(M|T)*P(T) = P(T|M)*P(M)$

$\\ P(M|T) = \frac{P(T|M)*P(M)}{P(T)}$

We have already know that

$\\ P(T|M) = 0.47\;P(M) = 0.22\;and\;P(T) = 0.204$ .

Therefore

$\\ P(M|T) = \frac{0.47*0.22}{0.204}$

$\\ P(M|T) = 0.50686 \approx 0.51$

Thus, the probability that a person is a Millennial given that they have tattoos is 0.5069 (50.69%) or about 0.51 (51%).

5 0

3 years ago

Heights of women have a bell-shaped distribution with a mean of 161 cm and a standard deviation of 7 cm. What percent of women f

harkovskaia [24]

Answer:b

Step-by-step explanation:d

504

5 0

2 years ago

Find the deference between

maxonik [38]

Answer:

$5520

Step-by-step explanation:

Given data

Principal= $24000

Rate=10%

time= 2 years

Firstly, the compound interest is given as

A=P(1+r)^t

A=24000(1+0.1)^2

A=24000(1.1)^2

A=24000*1.21

A=$29040

The simple interest is given as

A=P(1+rt)

A=24000(1+0.1*2)

A=24000(1.2)^2

A=24000*1.44

A=$34560

Hence the difference is

=34560-29040

=$5520

8 0

3 years ago

Which points are solutions??

IRINA_888 [86]

A, C and E all work in the equations. In order for them to work, you must use the ordered pair in each of the three situations. Below is the work for all of the correct answers.

Ordered Pair A : (1, -1)
y < x + 1
-1 < 1 + 1
-1 < 1 (TRUE)

y < 4
-1 < 4 (TRUE)

x < 6
1 < 6 (TRUE)

Ordered Pair C : (4, 2)
y < x + 1
2 < 4 + 1
2 < 5 (TRUE)

y < 4
2 < 4 (TRUE)

x < 6
5 < 6 (TRUE)

Ordered Pair E : (4, -2)
y < x + 1
-2 < 4 + 1
-2 < 5 (TRUE)

y < 4
-2 < 4 (TRUE)

x < 6
4 < 6 (TRUE)

5 0

3 years ago