A line having a slope of 3/4 passes through the point (-8,4). Write the equation of this line in slope-intercept form.

1 answer:

4 0

$General\ equation\ for\ line\ in\ slope\ intercept\ form:\\\\y=ax+b\\
a-slope\ \ \ a=\frac{3}{4}\\\\
y=\frac{3}{4}x+b\\\\Substitude\ point\ (-8,4)\\\\
4=\frac{3}{4}*(-8)+b\\\\
4=-\frac{24}{4}+b\ \ \ |Add\ -\frac{24}{4}\\\\
4+\frac{24}{4}=b\\\\
b=4+6=b\\\\
b=10\\\\
\textbf{Formula\ for\ line:}y=\frac{3}{4}x+10$

You might be interested in

Can y'all answer the questions at my profile? i need them done for online homework

Nuetrik [128]

So your parent hasn't joined you on the Brainly express to Achievement-ville. We'll get them on board. Parents are busy people, but you can be the boss and remind them. Remind them how Brainly boosts you with expert knowledge. Remind them that tons of students already get grade upgrades with Brainly Plus. Remind your parent of the power they have to raise you to your full potential. We think they would agree. You deserve every education advantage.

5 0

2 years ago

Read 2 more answers

Suppose four students miss an exam. They tell their instructor that they were carpooling to school together on the day of the ex

tia_tia [17]

Answer:

The probability they each indicate the same tire is $\frac{1}{64}=0.02$

Step-by-step explanation:

There will be 4 cases involved as there are 4 tires.

Probability of choosing front left tire is $\frac{1}{4}$ as there are a total of 4 tires and we need to choose 1.

Now, if all the four students chose the front left tire then the probability is the product of individual probabilities.

Therefore, probability that all 4 students chooses front left tire is:

$P(fl)=(\frac{1}{4})^4$

Similarly, the probabilities of choosing the remaining 3 tires by all the students would be:

$P(fr)=(\frac{1}{4})^4$ , $P(rl)=(\frac{1}{4})^4$ , $P(rr)=(\frac{1}{4})^4$

Therefore, the probability that they indicate the same tire is the sum of all these probabilities.

$P(\textrm{same tire by all})=P(fl)+P(fr)+P(rl)+P(rr)\\ P(\textrm{same tire by all})=(\frac{1}{4})^4\times 4\\ P(\textrm{same tire by all})=\frac{4}{4^4}=\frac{1}{4^3}=\frac{1}{64}=0.02$