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3 years ago

8

1. The edge of a hemisphere is an ___________.

1 answer:

Mars2501 [29]3 years ago

4 0

1) The edge of a hemisphere is a CIRCLE
2) A line segment with one endpoint on center of the circle and the other endpoint on the circle. RADIUS
3) In any circle, the DIAMETER is twice the length of the radius.
4) A three dimensional figure with all points the same distance from the center. SPHERE
5) A plane that intersects a sphere through its center divides the sphere into two halves called HEMISPHERE.

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(10+7)+30=47 what property is that?

chubhunter [2.5K]

17+30=47
47=47
That is the associative property of addition

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(8+8i)(-3+9i)<br> using imaginary numbers

lana66690 [7]

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2 years ago

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If a varies directly as the cube root of B and if a equals to 3 when B equals to 64 find the formula connecting the variables he

Brrunno [24]

Answer:

a=k1 $\sqrt[3]{B}$

B=125

Step-by-step explanation:

Given :

a=3

B=64

According to question

a ∝ $\sqrt[3]{B}$

therefore

a=k1 $\sqrt[3]{B}$ ........Eq(1)

K1= $\frac{a}{\sqrt[3]{B} }$ ......Eq(2)

Putting the value of a and B we get in Eq(2) we get

$K1=\frac{3}{4}$

Putting the value of k1 in Eq(1)

$a=\frac{3}{4}\sqrt{B}$ .......................Eq(3)

putting the value of a=15/4 IN Eq(3) we get

$\frac{15}{4}\ =\frac{3}{4} \sqrt[3]{B} \\\\\sqrt[3]{B}\ =\ 5\\Cubing\ both\ side\ we\ get\\B=125$

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3 years ago

Write the following expression without using<br> negative exponents.

solmaris [256]

Option B:

$$\frac{9{s^2} }{4 {m^3} {p^6}}$

Solution:

Given expression:

$$\frac{9 m^{-3} p^{-6}}{4 s^{-2}}$

To write this expression without negative exponents:

$$\frac{9 m^{-3} p^{-6}}{4 s^{-2}}$

Using exponent rule: $a^{-b}=\frac{1}{a^b}$

$$m^{-3}=\frac{1}{m^3}$

$$p^{-6}=\frac{1}{p^6}$

$$s^{-2}=\frac{1}{s^2}$

Substitute these in the expression.

$$\frac{9 m^{-3} p^{-6}}{4 s^{-2}}=\frac{9 \frac{1}{m^3} \frac{1}{p^6} }{4 \frac{1}{s^2} }$

Denominator of fraction in denominator goes to numerator.

Denominator of fraction in numerator goes to denominator.

Therefore, $s^2$ goes to numerator and $m^3p^6$ goes to denominator.

$$=\frac{9 \times {s^2} }{4 {m^3}\times{p^6}}$

$$=\frac{9{s^2} }{4 {m^3} {p^6}}$

Option B is the correct answer.

$$\frac{9 m^{-3} p^{-6}}{4 s^{-2}}=\frac{9{s^2} }{4 {m^3} {p^6}}$

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3 years ago

Find the volume of the figure

Aloiza [94]

Answer:

792 cm^3

Step-by-step explanation:

We can break up the shape into two shapes that we know how to find the volume - a triangular prism and a rectangular prism.

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