Answer:
see that there is no dependence on speed, so the work remains constant
Explanation:
Work is defined by the expression
W = F. d
where the boldface indicates vectors, this equation can be written in scalar form
W = f d cos θ
where θ is the angle between force and displacement.
We see that there is no dependence on speed, so the work remains constant
The power is
P = W / t
P = f d / t
p = F v
we see that the power is the one that depends on the speed of the body
The average speed will be:
Total distance travelled divided by time taken
Total distance (in metres)= 80+125+45=250
Total time (minutes) =10
250/10
=25
Thus Mary's average speed is 25 metres per minute.
Answer:
d = 6.43 cm
Explanation:
Given:
- Speed resistance coefficient in silicon n = 3.50
- Memory takes processing time t_p = 0.50 ns
- Information is to be obtained within T = 2.0 ns
Find:
- What is the maximum distance the memory unit can be from the central processing unit?
Solution:
- The amount of time taken for information pulse to travel to memory unit:
t_m = T - t_p
t_m = 2.0 - 0.5 = 1.5 ns
- We will use a basic relationship for distance traveled with respect to speed of light and time:
d = V*t_m
- Where speed of light in silicon medium is given by:
V = c / n
- Hence, d = c*t_m / n
-Evaluate: d = 3*10^8*1.5*10^-9 / 3.50
d = 0.129 m 12.9 cm
- The above is the distance for pulse going to and fro the memory and central unit. So the distance between the two is actually d / 2 = 6.43 cm
Answer:
Supongo que queremos determinar la carga de la carga de prueba.
Sabemos que la fuerza culombiana entre dos cargas q₁ y q₂, separadas por una distancia R, está dada por:
Aislandolo para una de las cargas, obtenemos:
En este caso sabemos:
fuerza atractiva, por lo que los signos de las cargas son opuestos.
q₁ = 5 mC
R = 35cm
F = 1.5 N
Kc = 9*10^9 N*m^2/C^2
Un primer paso, seria reescribir todos los valores en las mismas unidades.
Sabiendo que:
100cm = 1m
R = 35cm = (35/100) m = 0.35m
Y sabiendo que:
1mc = 1*10^(-6) C
Entonces:
q₁ = 5 mC = 5*1*10^(-6) C = 5*10^(-6) C
Ahora podemos reemplazar esos valores en la ecuación de la fuerza, para obtener el valor de la otra carga:
Y recordar que las cargas tienen signo opuesto, entonces la carga de la carga de prueba es:
q₂ = -4.08*10^-5 C
Answer:
North
Explanation:
In an electromagnetic wave, the direction of the wave, the direction of the electric field and the direction of the magnetic field are all perpendicular to each other.
Therefore, we can find the direction of the magnetic field by using the right hand rule. We have:
- Index finger: direction of motion of the wave --> toward the center of Earth
- middle finger: direction of the electric field --> west
- thumb: direction of the magnetic field --> north
So, the magnetic field points north.
