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fenix001 [56]
3 years ago
13

An object was thrown at a certain angle above the ground.It reaches a maximum height of 42.50 meters and hits back the ground 76

meters
1.find the time of flight
2.what is the initial velocity
3.find the angle of the projectile

Physics
1 answer:
aksik [14]3 years ago
7 0

Answer:

Explanation:  Please see my attached calculations.

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What is the net force on a 50-newton weight hanging on a string tied to the ceiling?
Lady bird [3.3K]
The net force on the hanging object is zero. If it were not zero, then the object would be accelerating in some direction.
4 0
3 years ago
An occupant of a car has a chance of surviving a crash if the deceleration during the crash is not more then 30 g. Calculate the
sweet [91]

Answer:

20,850 N

Explanation:

We can solve the problem by using second Newton's Law:

F=ma

where

F is the force

m is the mass

a is the acceleration

In this problem, we have:

m = 70 kg is the mass

a=-30 g=-30 (9.8 m/s^2)=-294 m/s^2 is the acceleration (which is negative, because it is a deceleration)

So, we can use the equation above to find the force:

F=(70 kg)(-294 m/s^2)=-20580 N

and the negative sign simply means that the force is in the opposite direction to the motion.

5 0
3 years ago
While tuning a string to the note C at 523 Hz, a piano tuner hears 2.00 beats/s between a reference oscillator and the string.
lara31 [8.8K]

Answer:

a)the possible frequencies are 521hz ,522hz, 523, 524hz,525hz

b) 526hz

c)0.989 or a 1.14% decrease in tension

Explanation:

a) While tuning a string at 523 Hz,piano tuner hears 2.00 beats/s between a reference oscillator and the string.

The possible frequencies of the string can be calculated by

fl=f' - B

where

fl= lower limit of the possible frequency

f'= frequency of the string

B= beat heard by the tuner

fl= 523hz + Or - (2beats/secs * 1hz/1beat per sc)

fl= 521hz or 525hz

So the possible frequencies are 521hz ,522hz, 523, 524hz,525hz

b)fl=f' - B

523hz= f' - 3

f'= 523 + 3= 526hz

c) The tension is directly proportional to the square of the frequencies

T1/T2 =f1^2/f2^2

523^2 / 526^2 = 0.989 or a 1.14% decrease in tensio

6 0
3 years ago
A car travels for 5.5 h at an average speed<br> of 75 km/h. How far did it travel?<br> T TE
ANEK [815]

Answer:

\boxed {\boxed {\sf 412.5 \ kilometers }}

Explanation:

Distance is the product of speed and time.

d=s*t

The speed of the car is 75 kilometers per hour. It traveled for 5.5 hours.

s= 75 \ km/hr \\t= 5.5 \ hr

Substitute the values into the formula.

d= 75 \ km/hr * 5.5 \ hr

Multiply. Note that the hours will cancel each other out.

d= 75 km * 5.5 \\d= 412.5 \ km

The car travelled <u>412.5 kilometers.</u>

5 0
3 years ago
if a ball with an original velocity of 0 is dropped from a tall structure and takes 7 Seconds to hit the ground what velocity do
krok68 [10]

a_y=\dfrac{v_y-v_{0y}}t\implies-9.81\,\dfrac{\mathrm m}{\mathrm s^2}=\dfrac{v_y-0}{7\,\mathrm s}\implies v_y=-68.7\,\dfrac{\mathrm m}{\mathrm s}

5 0
3 years ago
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