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fenix001 [56]
3 years ago
13

An object was thrown at a certain angle above the ground.It reaches a maximum height of 42.50 meters and hits back the ground 76

meters
1.find the time of flight
2.what is the initial velocity
3.find the angle of the projectile

Physics
1 answer:
aksik [14]3 years ago
7 0

Answer:

Explanation:  Please see my attached calculations.

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2 years ago
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T = ?
v1 = 0mph
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a =  \frac{v2 - v1}{t}&#10; \\ t =  \frac{v2-v1}{a}&#10; \\ t =  \frac{60mph - 0mph}{8.7mph/s}&#10; \\ t = 6.90s

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