An object was thrown at a certain angle above the ground.It reaches a maximum height of 42.50 meters and hits back the ground 76
meters
1.find the time of flight
2.what is the initial velocity
3.find the angle of the projectile
1.find the time of flight
2.what is the initial velocity
3.find the angle of the projectile
1 answer:
You might be interested in
From the question,
Using Impulse, the product of the constant force, F and time t equals the product of the mass of the body and change in velocity.
This implies that
You can also use the equation of linear motion,
But
Using Impulse, the product of the constant force, F and time t equals the product of the mass of the body and change in velocity.
This implies that
You can also use the equation of linear motion,
But
Answer:
The average speed of the elevator going down in the abandoned mine is 17.722mph.
Explanation:
If the elevator takes 90 seconds to descend a height of 713m, the average speed of the elevator is:
And if 1m/s is 2.23694mph, the average speed is:
.
Imagine an object is moving in one dimension on a number line, and for this we'll say that the numbers on the line are a metre apart. If the object moves from 2 m to 7 m, the change in position is 7-2=+5 metres. But if the object moves back from 7 m to 2 m, the change in position is 2-7=-5 metres. since 
, and time is always positive, velocity will be positive in one direction and negative in the other direction.