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neonofarm [45]
3 years ago
14

In physics lab, you measure three quantities: , , and . Suppose that =1.5 kg , =0.4 m , and =3.9 kg/m . Which of the mathematica

l combinations might be meaningful?
Physics
1 answer:
Novosadov [1.4K]3 years ago
5 0

Answer:

1.5 kg is mass, .4 m is volume, and 3.9 kg/m is volume

Explanation:

When looking at these types of problems, consider each part. First, whenever problems have measurements that have similar units of measurement, check if they are density related. In this case, we use the formula of D=M/V, where D stands for density, M stands for mass, and V stands for volume. Any measurements that relate to grams or pounds are mass. In solids, volume is written in cm or m, while in liquid, volume is considered in liters and gallons. Density is always mass divided by volume, so we know that 3.9 kg/m is the density due to the units provided.

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The power of the kettle was 1.5 kW. The 0.2kg heating element took 5 seconds to heat from 20 °C to 100 °C. Calculate the specifi
Debora [2.8K]

Answer:

Specific heat capacity, c = 468.75 J/Kg°C

Explanation:

Given the following data;

Power = 1.5 kW to Watts = 1.5 * 1000 = 1500 Watts

Time = 5 seconds

Mass = 0.2 kg

Initial temperature = 20°C

Final temperature = 100°C

To find specific heat capacity;

First of all, we would have to determine the energy consumption of the kettle;

Energy = power * time

Energy = 1500 * 5

Energy = 7500 Joules

Next, we would calculate the specific heat capacity of water.

Heat capacity is given by the formula;

Q = mcdt

Where;

  • Q represents the heat capacity or quantity of heat.
  • m represents the mass of an object.
  • c represents the specific heat capacity of water.
  • dt represents the change in temperature.

dt = T2 - T1

dt = 100 - 20

dt = 80°C

Making c the subject of formula, we have;

c = \frac {Q}{mdt}

Substituting into the equation, we have;

c = \frac {7500}{0.2*80}

c = \frac {7500}{16}

<em>Specific heat capacity, c = 468.75 J/Kg°C</em>

7 0
3 years ago
Who was responsible for arriving at the
Anuta_ua [19.1K]

Answer:

James Prescott Joule

James Prescott Joule, (born December 24, 1818, Salford, Lancashire [now in Greater Manchester], England—died October 11, 1889, Sale, Cheshire), English physicist who established that the various forms of energy—mechanical, electrical, and heat—are basically the same and can be changed one into another.James Prescott Joule experimented with engines, electricity and heat throughout his life. Joule's findings resulted in his development of the mechanical theory of heat and Joule's law, which quantitatively describes the rate at which heat energy is produced from electric energy by the resistance in a circuit.

5 0
4 years ago
An early submersible craft for deep-sea exploration was raised and lowered by a cable from a ship. When the craft was stationary
Assoli18 [71]

Answer:

The tension in the cable when the craft was being lowered to the seafloor is 4700 N.

Explanation:

Given that,

When the craft was stationary, the tension in the cable was 6500 N.

When the craft was lowered or raised at a steady rate, the motion through the water added an 1800 N.

The drag force of 1800 N will act in the upward direction. As it was lowered or raised at a steady rate, so its acceleration is 0. As a result, net force is 0. So,

T + F = W

Here, T is tension

F = 1800 N

W = 6500 N

Tension becomes :

T=W-F\\\\T=6500-1800\\\\T=4700\ N

So, the tension in the cable when the craft was being lowered to the seafloor is 4700 N.

7 0
3 years ago
The strength of gravitational force is affected by the mass of objects and which of the following?
gizmo_the_mogwai [7]

Answer:

The distance between two objects

Explanation:

Depending on how far away or how close two objects are will affect the gravity.

6 0
3 years ago
Read 2 more answers
*Look at attachment for photo of object**
prohojiy [21]

A. The magnitude of the spring force (in N) acting upon the object is 15.9 N

B. The magnitude of the object's acceleration (in m/s²) is 30.58 m/s²

C. The direction of the acceleration vector points toward the equilibrium position (i.e., to the left in the figure).

<h3>A. How to determine the force </h3>
  • Extension (e) = 0.150 m
  • Spring constant (K) = 106 N/m
  • Force (F) = ?

F = Ke

F = 106 × 0.15

F = 15.9 N

<h3>B. How to determine the acceleration</h3>
  • Mass (m) = 0.52 Kg
  • Force (F) = 15. 9 N
  • Acceleration (a) =?

F = ma

Divide both sides by m

a = F / m

a = 15.9 / 0.52

a = 30.58 m/s²

<h3>C. How to determine the direction of the acceleration vector</h3>

Considering the diagram, we can see that the spring was pulled away from the equilibrium point.

Thus, when the spring is released, it will move toward the equilibrium point. This is also true about the acceleration.

Therefore, we can conclude that the direction of the acceleration vector is towards the equilibrium point.

Learn more about spring constant:

brainly.com/question/9199238

#SPJ1

3 0
2 years ago
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