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11111nata11111 [884]
3 years ago
15

WILL GIVE BRAINLEST

Mathematics
1 answer:
Gnoma [55]3 years ago
6 0
You will need 3 to 4 yards of concrete for a footer that's 1 foot wide and 12 inches deep. 
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Need help on this question
Vedmedyk [2.9K]

Answer:

angle 4

Step-by-step explanation:

7 0
3 years ago
Find the volume of the cylinder. Give you answers both in terms of π and rounded to the nearest tenth.
Ugo [173]

Answer:

Step-by-step explanation:

The formula for determining the volume of a cylinder is expressed as

Volume = πr²h

Where

r represents the radius of the cylinder.

h represents the height of the cylinder.

π is a constant whose value is 3.14

From the information given,

Height = 19 cm

Since the base area is 24π cm², we would determine its radius by applying the formula,

Area of circle = πr²

24π = πr²

r² = 24

r = √24

Therefore,

Volume of cylinder = π × (√24)² × 19 = 456π cm³

It is approximately

456 × 3.14 = 1431.8 cm³

3 0
3 years ago
A circular quilt is made from 113.04 square feet of fabric. How much trim is needed to go around it’s edge?
erik [133]

Hey there!

We are looking for the circumference of the circle, which is the distance around it. We are given the area, which is the radius squared times pi.

First, we need to undo the area to find our radius.

113.04/3.14=36

We square root this to find the radius.

√36=6

Our radius is six. To find the circumference, we need to multiply the diameter by pi. The diameter is twice the radius.

6*2=12

12*3.14=37.68

Therefore, we will need 37.68 feet of trim to around the edge of the quilt.

I hope this helps!

6 0
3 years ago
Find f(-2)for f(x)=5*3^x
damaskus [11]

f ( - 2 ) = 5 × 3^( - 2 )

f ( - 2 ) = 5 × 1/9

f ( - 2 ) = 5/9

5 0
3 years ago
At what values of x does f(x) = x^3 - 2x^2 -4x+1 satisfy the mean value theorwm on [0,1]
denis-greek [22]

Answer:

x=1/3

Step-by-step explanation:

A function f is given as

f(x) = x^3-2x^2-4x+1 in the interval  [0,1]

This function f being an algebraic polynomial is continuous in the interval [0,1] and also f is differntiable in the open interval (0,1)

Hence mean value theorem applies for f in the given interval

f(1) = 1-2-4+1 = -4\\f(0) = 1

The value

\frac{f(1)-f(0)}{1-0} =\frac{-4-1}{1} =-5

Find derivative for f

f'(x) = 3x^2-4x-4

Equate this to -5 to check mean value theorem

3x^2-4x-4=-5\\3x^2-4x+1=0\\\\(x-1)(3x-1) =0\\x= 1/3 : x = 1

We find that 1/3 lies inside the interval (0,1)

4 0
3 years ago
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