Step-by-step explanation:
Since PT = 2PM and AR = 2AD,
The midsegment MD must be the average of PA and TR:
Therefore we have
2(20x + 4) = 10 + (34x + 16)
=> 40x + 8 = 34x + 26
=> 6x = 18
=> x = 3
Hence length of MD
= 40(3) + 8 = 128.
Radius is 6.5 and the diameter is 13
Answer:
There are 118 plants that weight between 13 and 16 pounds
Step-by-step explanation:
For any normal random variable X with mean μ and standard deviation σ : X ~ Normal(μ, σ)
This can be translated into standard normal units by :
Let X be the weight of the plant
X ~ Normal( 15 , 1.75 )
To find : P( 13 < X < 16 )

= P( -1.142857 < Z < 0.5714286 )
= P( Z < 0.5714286 ) - P( Z < -1.142857 )
= 0.7161454 - 0.1265490
= 0.5895965
So, the probability that any one of the plants weights between 13 and 16 pounds is 0.5895965
Hence, The expected number of plants out of 200 that will weight between 13 and 16 = 0.5895965 × 200
= 117.9193
Therefore, There are 118 plants that weight between 13 and 16 pounds.
Answer:
8 ft
Step-by-step explanation:
60 of each item
Step-by-step explanation:
5 boxes of pencils, 6 boxes of markers, 15 boxes of notebooks, 10 boxes of erasers, and four boxes of folders