2x^2 + 8x - 12 = 0..divide by 2
x^2 + 4x - 6 = 0
x^2 + 4x = 6...add 4 to both sides of the equation
x^2 + 4x + 4 = 6 + 4
(x + 2)^2 = 10....<== ur constant is 10
x + 2 = (+-)sqrt 10
x = -2 (+ - ) sqrt 10
x = -2 + sqrt 10
x = -2 - sqrt 10
True
using the converse of Pythagoras' identity
Given 3 sides of a triangle, if the longest side squared is equal to the sum of the squares of the other 2 sides then triangle is right.
longest side squared = 26² = 676
sum of other 2 sides squared = 24² + 10² = 576 + 100 = 676
Hence triangle is right
30 70 90 are the angles of the triangle hope this is helpful
Answer:
The solutions are π/4, 3π/4,5π/4,7π/4
Step-by-step explanation:
The given equation is
6sin²(x) = 3
Divide by 6 to get:
This implies that;
If
in the first quadrant
in the second quadrant.
If
in the third quadrant
Answer: A
2x^2+2x-8 is the quotient when x+3 divides P(x)
=> P(x) = (2x² + 2x -8)(x + 3) = 2(x² + x - 4)(x + 3) = (x² + x - 4) (2x + 6)
=> the quotient when 2x+6 divides p(x) is x² + x - 4
Step-by-step explanation:
