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faltersainse [42]
3 years ago
15

Marcus and his friends are having

Mathematics
1 answer:
Blizzard [7]3 years ago
4 0

Answer:

S = 1.25

B = 3.50

Step-by-step explanation:

I assume you need to know how much a burger and how much a soda is.

Basically it's a system of equations.

5B + 9S = 28.75

10B + 10S = 47.5

There are a few ways to do this, if you like I can show another, but this is how I usually solve a normal system of equations.

First solve for one variable in one equation.  I am going to choose to solve for B in 10B + 10S = 47.5

10B + 10S = 47.5 (divide the whole thing by 10)

B + S = 4.75 (subtract S from both sides)

B = 4.75 - S

Now plug this B into the other equation.

5B + 9S = 28.75

5(4.75 - S) + 9S = 28.75

23.75 - 5S + 9S = 28.75 (Now just solve for S

4S = 5

S = 5/4

S = 1.25

Now plug THIS back into the first one.

B = 4.75 - S

B = 4.75 - 1.25

B = 3.50

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In an article regarding interracial dating and marriage recently appeared in a newspaper. Of 1719 randomly selected adults, 311
Bingel [31]

Answer:

Step-by-step explanation:

Hello!

The parameter of interest in this exercise is the population proportion of Asians that would welcome a person of other races in their family. Using the race of the welcomed one as categorizer we can define 3 variables:

X₁: Number of Asians that would welcome a white person into their families.

X₂: Number of Asians that would welcome a Latino person into their families.

X₃: Number of Asians that would welcome a black person into their families.

Now since we are working with the population that identifies as "Asians" the sample size will be: n= 251

Since the sample size is large enough (n≥30) you can apply the Central Limit Theorem and approximate the variable distribution to normal.

Z_{1-\alpha /2}= Z_{0.975}= 1.965

1. 95% CI for Asians that would welcome a white person.

If 79% would welcome a white person, then the expected value is:

E(X)= n*p= 251*0.79= 198.29

And the Standard deviation is:

V(X)= n*p*(1-p)= 251*0.79*0.21=41.6409

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You can construct the interval as:

E(X)±Z₁₋α/₂*√V(X)

198.29±1.965*6.45

[185.62;210.96]

With a 95% confidence level, you'd expect that the interval [185.62; 210.96] contains the number of Asian people that would welcome a White person in their family.

2. 95% CI for Asians that would welcome a Latino person.

If 71% would welcome a Latino person, then the expected value is:

E(X)= n*p= 251*0.71= 178.21

And the Standard deviation is:

V(X)= n*p*(1-p)= 251*0.71*0.29= 51.6809

√V(X)= 7.19

You can construct the interval as:

E(X)±Z₁₋α/₂*√V(X)

178.21±1.965*7.19

[164.08; 192.34]

With a 95% confidence level, you'd expect that the interval [164.08; 192.34] contains the number of Asian people that would welcome a Latino person in their family.

3. 95% CI for Asians that would welcome a Black person.

If 66% would welcome a Black person, then the expected value is:

E(X)= n*p= 251*0.66= 165.66

And the Standard deviation is:

V(X)= n*p*(1-p)= 251*0.66*0.34= 56.3244

√V(X)= 7.50

You can construct the interval as:

E(X)±Z₁₋α/₂*√V(X)

165.66±1.965*7.50

[150.92; 180.40]

With a 95% confidence level, you'd expect that the interval [150.92; 180.40] contains the number of Asian people that would welcome a Black person in their family.

I hope it helps!

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Answer:

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Hola! Este línea hace no intersecarese con el par do puntos dada. ¿Ver?
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