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saw5 [17]
3 years ago
13

Which is in the ten thousandth position in 12.0002

Mathematics
1 answer:
balu736 [363]3 years ago
4 0

Answer:

2 is in the ten thousandths

Step-by-step explanation:

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A paint company mixes it's paint with water to create more paint per gallon. They currently have ten gallon jugs which contain 1
Karo-lina-s [1.5K]
<h3>Answer:  1.25 gallons</h3>

==================================

Explanation:

They currently have ten gallon jugs that contain 10% water, so this means 0.10*10 = 1 gallon of the jug is water and the other 10-1 = 9 gallons is paint. This is assuming the cans are just paint and water.

The ratio of paint to water is 90:10 which reduces to 9:1

Often it helps to reduce as much as possible, but it's actually more handy in this case to keep it at 90:10 so you can see the two parts add back up to 100%

--------------

Let x be the amount of water we add. This amount is in gallons.

We start off with 1 gallon of water and it bumps up to 1+x gallons of water.

The overall amount of 10 gallons also bumps up to 10+x gallons.

We want a ratio of 80:20 this time, so we want 20 parts water and 80 parts paint. In other words, we want 20/(20+80) = 20/100 = 20% water

Divide (1+x) over (10+x) to get (1+x)/(10+x). This represents the fraction of water. We want this fraction to be equal to 0.20, which is the 20% water amount. It is also equal to 20/100.

--------------

(1+x)/(10+x) = 20/100

100(1+x) = 20(10+x) ... cross multiply

100+100x = 200+20x ... distribute

100x-20x = 200-100

80x = 100

x = 100/80 ... divide both sides by 80

x = 1.25

You need to add 1.25 gallons of water

--------------

If you add 1.25 gallons of water, then,

amount of water = 1+x = 1+1.25 = 2.25

amount of paint&water = 10+x = 10+1.25 = 11.25

So you'll have 2.25 gallons of water out of 11.25 gallons of water&paint mix

2.25/11.25 = 0.2 = 20% water

This confirms our answer.

--------------

Extra info:

1.25 gallons = 1 gallon + 1/4 gallon

1.25 gallons = 1 gallon + 1 quart

This is because 1 gallon = 4 quarts, so 1 quart = 1/4 gallon.

5 0
3 years ago
Write the expression as the sin or cosine of an angle.<br> sin pi/3 cos pi/7 - sin pi/7 cos pi/3
postnew [5]

sin(4π21). Explanation: Notice that this fits the form of the sine subtraction formula: sin(A−B)=sin(A)cos(B)−cos(A)sin(B).

5 0
2 years ago
Can someone help me with this
NISA [10]

Answer:

19-6j/5

Step-by-step explanation:

6 0
2 years ago
Estimate the product of 17 and 234<br> 4,000<br> 2,000<br> 6,000<br> 3,000
zubka84 [21]

Answer:

I believe the answer is D?

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Question 1- Whats the derivative of: A) f(x)= 4 cos(x) + ln(x+1)<br> B) f(x)= sec(x) X tg(x)
Kryger [21]

The derivatives for this problem are given as follows:

a) f^{\prime}(x) = -4\sin{x} + \frac{1}{x + 1}

b) f^{\prime}(x) = \sec{x}\tan^{2}{x} + \sec^3{x}.

<h3>What is the derivative of the sum?</h3>

The derivative of the <u>sum is the sum of the derivatives</u>.

In this problem, the function is:

f(x) = 4\cos{x} + \ln{(x + 1)}

Using a derivative table for the derivatives of the cosine and the ln, the derivative of the function is:

f^{\prime}(x) = (4\cos{x})^{\prime} + (\ln{(x + 1)})^{\prime}

f^{\prime}(x) = -4\sin{x} + \frac{1}{x + 1}

What is the product rule?

The derivative of the product is given as follows:

(f(x) \times g(x))^{\prime} = f^{\prime}(x)g(x) + g^{\prime}(x)f(x)

In this problem, we have that:

  • f(x) = \sec{x}, f^{\prime}(x) = \sec{x}\tan{x}.
  • g(x) = \tan{x}, f^{\prime}(x) = \sec^2{x}.

Hence the derivative is:

f^{\prime}(x) = \sec{x}\tan^{2}{x} + \sec^3{x}.

More can be learned about derivatives at brainly.com/question/2256078

#SPJ1

4 0
2 years ago
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