12, 2, 4, and 7. The coefficients in the expression 12xy³+2x⁵y+4x⁵y²+7x⁵y are 12, 2, 4, and 7.
In order to solve this problem we have to know that the coefficients is a factor linked to a monomial. For example, the first monomial of the equation is 12xy³ the coeffcient of xy³ is 12.
Answer:
P(x < 5) = 0.70
Step-by-step explanation:
Note: The area under a probability "curve" must be = to 1.
Finding the sub-area representing x < 5 immediately yields the desired probability.
Draw a dashed, vertical line through x = 5. The resulting area, on the left, is a trapezoid. The area of a trapezoid is equal to:
(average length)·(width, which here is:
2 + 5
----------- · 0.02 = (7/2)(0.2) = 0.70
2
Thus, P(x < 5) = 0.70
Answer:
D
Step-by-step explanation:
because we know that angle EOD is less the 90 so that means that it is complementary. For AOB it is the same but we can check by adding 35 plus x plus 90 =180 degrees so 35+90=125 x=180-125=55 so x=55 and 55 is less then 90 so it is a complementary angle.
Since A = bh
and A = 198 and b = 18?
h = A/b
= 198/18
= 11
