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erastovalidia [21]
3 years ago
14

The graph shows a probability distribution. What is P(X<5)

Mathematics
1 answer:
Thepotemich [5.8K]3 years ago
7 0

Answer:

P(x < 5) = 0.70

Step-by-step explanation:

Note:  The area under a probability "curve" must be = to 1.

Finding the sub-area representing x < 5 immediately yields the desired probability.

Draw a dashed, vertical line through x = 5.  The resulting area, on the left, is a trapezoid.  The area of a trapezoid is equal to:

 (average length)·(width, which here is:

  2 + 5

----------- · 0.02  =  (7/2)(0.2) =  0.70

      2

Thus, P(x < 5) = 0.70

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Calculate the volume of the figure.
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Answer: The volume is 33 cubic centimeters.

Step-by-step explanation:

First find the volume of the square pyramid on top of the cube. To find the volume of the square pyramid you use the volume  a^2*h/3 a is the side length of the base of the square pyramid and h is the height all divide by 3.

So we can say that the side length of the base of the square pyramid is 3 because it has the same side length base as the cube.

V= 3^2 * 2 /3

V= 9 * 2 /3

V= 18/3

v= 6  

So the volume of the square pyramid is 6 so now we need to find the volume of the cube and add them together.

Volume of the a cube uses the formula s^3 where s is the side length.

V= 3^3

v= 3*3*3

v= 27  

The volume of the cube is 27.

Add 6 and 27 to find the total volume.

6 +27 = 33

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3 years ago
What’s the gcf (greatest common factor) of this expression
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Step-by-step explanation:

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2 years ago
Read 2 more answers
Solve the inequality 2x&gt;30+5/4x
insens350 [35]

Answer:

Step-by-step explanation:

2x > 30+\frac{5}{4x} \\2x-\frac{5}{4x} > 30\\\frac{8x^2-5}{4x} > 30\\case~1\\if~x > 0\\8x^2-5 > 120x\\8x^2-120x > 5\\x^2-15x > \frac{5}{8} \\adding~(-\frac{15}{2} )^2~to~both~sides\\(x-\frac{15}{2} )^2 > \frac{5}{8}+\frac{225}{4} \\(x-\frac{15}{2} )^2 > \frac{455}{8} \\x-\frac{15}{2} < -\sqrt{\frac{455}{8} }  \\x < \frac{15}{2}-\sqrt{\frac{455}{8} } \\or~x < 0\\rejected~as~x > 0

x-\frac{15}{2} > \sqrt{\frac{455}{8} } \\x > \frac{15}{2} +\sqrt{\frac{455}{8} }

case~2

if~x < 0\\8x^2-5 < 120x\\8x^2-120x < 5\\x^2-15x < \frac{5}{8} \\adding~(-\frac{15}{2} )^2\\(x-\frac{15}{2} )^2 < \frac{5}{8} +(-\frac{15}{2} )^2\\|x-\frac{15}{2} | < \frac{5+450}{8} \\-\sqrt{\frac{455}{8} } < x-\frac{15}{2} < \sqrt{\frac{455}{8} } \\\frac{15}{2} -\sqrt{\frac{455}{8} } < x < \frac{15}{2} +\sqrt{\frac{455}{8} } \\but~x < 0\\7.5-\sqrt{\frac{455}{8} } < x < 0

8 0
1 year ago
I will give brainliest and A LOT OF POINTS please help!!!!!!!!!!!!!!!!!
DedPeter [7]

Answer:

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Step-by-step explanation:

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30÷6=5

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2 years ago
A student was asked to use the formula for the perimeter of a rectangle, p = 2l 2w, to solve for l. the student came up with an
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