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Jet001 [13]
3 years ago
7

Please Help! Answer the question on this picture!

Mathematics
1 answer:
Debora [2.8K]3 years ago
6 0

Answer:

it dilated by two

Step-by-step explanation:

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Ashley bought 2 1/7 lb of tomatoes, 3 2/3 lb of lettuce, and 3 1/3 lb of spinach to make a salad. How many pounds of vegetables
blsea [12.9K]
9 1/7 lb

You can convert the mixed numbers to solve it easier! :)
7 0
3 years ago
I really need help plzzzzz​
Marianna [84]

Answer:

  • All similar, see below

Step-by-step explanation:

Q1

<u>Angles</u>

  • 26° & 64° & 90°
  • AA similarity

Q2

<u>Ratios of corresponding sides:</u>

  • 6/8 = 9/12 = 12/16 ⇒ 3/4
  • SSS similarity

Q3

<u>Angle C is vertical</u>

  • ∠ACB ≅ ∠DCE

<u>Ratios of corresponding sides:</u>

  • 9/15 = 18/30 ⇒ 3/5
  • SAS similarity
6 0
3 years ago
Graph the system of inequalities. Then use your graph to identify the point that
Alona [7]

Answer:

Step-by-step explanation:

b it is b just do what u think is right because i think u can do it no matter what

8 0
3 years ago
Set up and solve an equation for the value of x. Use the value of x and a relevant angle relationship in the diagram
Fudgin [204]

Answer:

x and EAF are 27 degrees

Step-by-step explanation:

Since GAF is a right angle as indicated by the little square, GAC and CAF must add up to 90 degrees. Therefore, x is 90-63=27 degrees. The situation is the same for angle EAF. Hope this helps!

7 0
3 years ago
A particle is moving along a projectile path where the initial height is 96 feet with an initial speed of 16 feet per second. Wh
leonid [27]

Answer:

The maximum height of the particle is 100 ft

A is correct

Step-by-step explanation:

A particle is moving along a projectile path where the initial height is 96 feet with an initial speed of 16 feet per second.

The standard equation of parabolic projectile.

h(t)=-16t^2+v_0t+h_0

where,

v_0=16\ ft/s

h_0=96\ ft

h(t)=-16t^2+16t+96

So, we get the parabolic equation of path.

The maximum value at vertex.

t=-\dfrac{b}{2a}

t=-\dfrac{16}{-32}=\dfrac{1}{2}

Maximum at t=0.5

h(0.5)=-16(0.5)^2+16(0.5)+96

h(0.5)=100

Hence, The maximum height of the particle is 100 ft

4 0
3 years ago
Read 2 more answers
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