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erastovalidia [21]
3 years ago
10

If C = 5h-2, calculate C when h = 12

Mathematics
1 answer:
Lyrx [107]3 years ago
3 0
C=5h-2, and we are given that h=12, so we just substitute that value for h in the equation...

c=5(12)-2

c=60-2

c=58
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Find m∠QPR..........
dexar [7]

Hey there! :)

Answer:

m∠QPR = 25°.

Step-by-step explanation:

Given:

m∠QPS = 40°

m∠RPS = 8x + 7°

m∠QPR = 9x + 16°

m∠QPS = m∠RPS + m∠QPR, therefore:

40° = 8x + 7° + 9x + 16°

Combine like terms:

40° = 17x + 23°

Subtract 23° from both sides:

17° = 17x°

Divide both sides by 17:

x = 1°

If m∠QPR = 9x + 16°, substitute in 1 for 'x':

9(1) + 16 = 9 + 16 = 25°.

3 0
3 years ago
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Diano4ka-milaya [45]
The proportion is 0.4401.

We find z-scores that correspond with both ends of this interval.  Z-scores are given using the formula:

z=\frac{X-\mu}{\sigma}

For the lower end, 

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The proportion of scores to the left of this number is 0.2514.

For the higher end, the z-score is

z=\frac{4.4-4.1}{0.6}=\frac{0.3}{0.6}=0.5

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3 0
3 years ago
Find the value of sin(a/2) if cosa= 12/13<br>​
daser333 [38]

Answer: sin\frac{a}{2} = ± \frac{1}{\sqrt{26} }

Step-by-step explanation:

We very well know that,

cos2A=1−2sin²A

⟹ sinA = ±\sqrt{(1-} \frac{cos2A}{2} )

As required,  set A = \frac{a}{2}   &   cos a=  \frac{12}{13}    ,thus we get

sin \frac{a}{2} =± \sqrt{\frac{1-cos a}{2} }  

∴ sin\frac{a}{2} =±\sqrt{\frac{1-\frac{12}{13} }{2} } = ± \frac{1}{\sqrt{26} }

   since ,360° < \frac{a}{2} <450°

             ,180° < \frac{a}{2} <225°

Now, we are to select the value with the correct sign. It's is obvious from the above constraints that the angle a/2 lies in the III-quadrant where 'sine' has negative value, thus the required value is negative.

hope it helped!

   

5 0
3 years ago
By cutting away identical squares from each corner of a rectangular piece of cardboard and folding up the resulting flaps, an op
LenaWriter [7]
Try sketching the cardboard piece labeling each side. when folded, the height of the box is x, the length is now (13 - 2x), the width is now (6 - 2x) after cutting out the squares from each corner.

volume = length*width*height

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3 0
3 years ago
What is <img src="https://tex.z-dn.net/?f=%28x%E2%88%928%29%282x%2B3%29%3D%283x%E2%88%925%29%28x%2B4%29%5C%5C" id="TexFormula1"
Softa [21]

Answer:

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I assume you meant (x-8)(2x+3) = (3x-5)(x+4).

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Subtract 3x^2 from both sides:

-x^2 - 13x - 24 = 7x - 20

Subtract 7x from both sides:

-x^2 - 20x - 24 = -20

Add 20 to both sides:

-x^2 - 20x -4 = 0   This is the desired quadratic equation.

6 0
3 years ago
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