Hey there! :)
Answer:
m∠QPR = 25°.
Step-by-step explanation:
Given:
m∠QPS = 40°
m∠RPS = 8x + 7°
m∠QPR = 9x + 16°
m∠QPS = m∠RPS + m∠QPR, therefore:
40° = 8x + 7° + 9x + 16°
Combine like terms:
40° = 17x + 23°
Subtract 23° from both sides:
17° = 17x°
Divide both sides by 17:
x = 1°
If m∠QPR = 9x + 16°, substitute in 1 for 'x':
9(1) + 16 = 9 + 16 = 25°.
The proportion is 0.4401.
We find z-scores that correspond with both ends of this interval. Z-scores are given using the formula:

For the lower end,

The proportion of scores to the left of this number is 0.2514.
For the higher end, the z-score is

The proportion of scores to the left of this number is 0.6915.
To find just the proportion of scores between these two, we subtract;
0.6915-0.2514 = 0.4401.
Answer: sin
= ±
Step-by-step explanation:
We very well know that,
cos2A=1−2sin²A
⟹ sinA = ±
As required, set A =
& cos a=
,thus we get
sin
=±
∴ sin
=±
= ±
since ,360° <
<450°
,180° <
<225°
Now, we are to select the value with the correct sign. It's is obvious from the above constraints that the angle a/2 lies in the III-quadrant where 'sine' has negative value, thus the required value is negative.
hope it helped!
Try sketching the cardboard piece labeling each side. when folded, the height of the box is x, the length is now (13 - 2x), the width is now (6 - 2x) after cutting out the squares from each corner.
volume = length*width*height
V(x) = x(13 - 2x)(6 - 2x)
Answer:
-x^2 - 20x -4 = 0
Step-by-step explanation:
I assume you meant (x-8)(2x+3) = (3x-5)(x+4).
Perform the two indicated multiplications and then combine like terms:
2x^2 + 3x - 16x - 24 = 3x^2 + 12x - 5x - 20
Combine the x terms on each side:
2x^2 - 13x - 24 = 3x^2 + 7x - 20
Subtract 3x^2 from both sides:
-x^2 - 13x - 24 = 7x - 20
Subtract 7x from both sides:
-x^2 - 20x - 24 = -20
Add 20 to both sides:
-x^2 - 20x -4 = 0 This is the desired quadratic equation.