Answer:
322
Step-by-step explanation:
We have,
a^3+b^3=(a+b)^3-3ab(a+b)
p+1/p=7
Now,
p^3+1/p^3=(p+1/p)^3-3*p*1/p(p+1/p)
=7^3-3(7)=343-21=322
The best way to estimate large numbers is to find out how many units is in the number. For example, when you are dealing with millions you need to estimate the number of items closest to the large number. Ex. 1, 899,000 estimating this number is basically saying close to 2 million because the number to the right is higher then 5 so the number goes up.
Answer:
D
Step-by-step explanation:
Note there is a common difference d between consecutive terms in the sequence, that is
d = 2 - 5 = - 1 - 2 = - 4 - (- 1) = - 3
This indicates that the sequence is arithmetic with n th term
= a₁ + (n - 1)d
where a₁ is the first term and d the common difference
Here a₁ = 5 and d = - 3, thus
= 5 - 3(39) = 5 - 117 = - 112 → D
Answer:
0.182 probability that the Yankees will win when they score fewer than 5 runs
Step-by-step explanation:
We use the conditional probability formula to solve this question. It is

In which
P(B|A) is the probability of event B happening, given that A happened.
is the probability of both A and B happening.
P(A) is the probability of A happening.
In this problem:
When the Yankees score less than 5 runs, either they win, or they lose. The sum of these probabilities is 1.
Probability they lose:
Event A: Scoring fewer than 5 runs.
Event B: Losing
The probability that the Yankees will score 5 or more runs in a game is 0.56.
So 1 - 0.56 = 0.44 probability the Yankees score fewer than 5 runs.
This means that 
The probability that the Yankees lose and score fewer than 5 runs is 0.36.
This means that 
Then the probability they lose is:

Probability they win:
p + 0.818 = 1
p = 0.182
0.182 probability that the Yankees will win when they score fewer than 5 runs