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3 years ago

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Mr. Garcia has been asked to give 6 desks to Mrs. Johnson. He needs to keep at least 17 desks for his students. He created a mod

el to find x, the number of desks he must have in order to give 6 desks to Mrs. Johnson. Which inequality represents the model for this situation?

1 answer:

kumpel [21]3 years ago

8 0

Answer:

The inequality which represents the model for this situation is $x-6\geq 17$ .

Step-by-step explanation:

Let Mr. Garcia has $x$ number of desks initially.

He has been asked to give $6$ desks to Mrs. Johnson.

Also, he needs to keep at least $17$ desks for his students.

So, after giving $6$ desks to Mrs. Johnson from the total number of desks he has, he must have at least $17$ desks for his students.

Therefore, the inequality is: $x-6\geq 17$ .

Hence, the inequality which represents the model for this situation is $x-6\geq 17$ .

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Select the answer that expresses the result of this calculation with the correct number of significant figures. 13.602 x 1.90 x

Marta_Voda [28]

Solution:

Given expression: ( $\frac{13.602*1.90*3.06}{4.2*1.4097}$ )

= $\frac{79.1}{5.9}$

= 13

In the expression of 13.602*1.90*3.06 will have only 3 significant figure because the number 1.90 has only 3 significant figure .

In the expression of 4.2*1.4097 will have only 2 significant figure because the number 4.2 has only 2 significant figure.

In the result of 79.1/5.9 will have only 2 significant figure because the number 5.9 has only 2 significant figure.

Hence, in the result there are only 2 significant figure.

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3 years ago

HELP PLEASE !!! Place each expression under the equivalent expression in the table.

tino4ka555 [31]

Answer:

Option 3,5 are under first expression and Option 1,2 are under second expression.

Step-by-step explanation:

1). $\frac{(x-4)(x+2)}{x^{2}+5x+6}+\frac{-3x^{2}+24x-20}{(x+3)(4x-5)}$

$=\frac{(x-4)(x+2)}{(x+3)(x+2)}+\frac{-3x^{2}+24x-20}{(x+3)(4x-5)}$ $=\frac{(x-4)}{(x+3)}+\frac{-3x^{2}+24x-20}{(x+3)(4x-5)}$

$=\frac{(x-4)(4x-5)-3x^{2}+24x-20}{(x+3)(4x-5)}$

$=\frac{4x^{2}-5x-16x+20-3x^{2}+24x-20}{(x+3)(4x-5)}$ $=\frac{x^{2}+3x}{(x+3)(4x-5)}$

$=\frac{x(x+3)}{(x+3)(4x-5)}=\frac{x}{4x-5}$

2). $\frac{3x}{4x-5}-\frac{4x^{2}}{8x^{2}-10x}=\frac{3x}{4x-5}-\frac{4x}{8x-10}$ $=\frac{3x(8x-10)-4x(4x-5)}{(4x-5)(8x-10)}$

$=\frac{24x^{2}-30x-16x^{2}+20x}{(4x-5)(8x-10)}$

$=\frac{8x^{2}-10x}{(4x-5)(8x-10)}$ $=\frac{x(8x-10)}{(4x-5)(8x-10)}=\frac{x}{4x-5}$

3). $\frac{6x^{2}}{x^{2}-7x+10}\div \frac{2x}{x-5}$

$=\frac{6x^{2}}{x^{2}-7x+10}\times \frac{x-5}{2x}$

$=\frac{3x(x-5)}{x^{2}-7x+10}$

$=\frac{3x(x-5)}{(x-5)(x-2)}=\frac{3x}{x-2}$

4). $\frac{-x}{4x-5}-\frac{4x^{2}}{16x^{2}-22x}$

$=\frac{-x}{4x-5}-\frac{2x}{8x-11}$

$=\frac{-x(8x-11)-2x(4x-5)}{(4x-5)(8x-11)}$

$=\frac{-8x^{2}+11x-8x^{2}+10x}{(4x-5)(8x-11)}$

$=\frac{-16x^{2}+21x}{(4x-5)(8x-11)}=\frac{-x(16x-21)}{(4x-5)(8x-11)}$

5). $\frac{3x^{2}}{x+3}\times \frac{2(x+3)}{2x^{2}-4x}$

$=\frac{6x^{2}(x+3)}{2x(x+3)(x-2)}=\frac{3x}{x-2}$

6). $\frac{5x^{2}}{x-2}\times \frac{2x+6}{8x^{2}-4x}$

$=\frac{10x^{2}(x+3)}{4x(x-2)(2x-1)}$

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3 years ago

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notsponge [240]

Answer:

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Step-by-step explanation:

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3 years ago

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Use unit multipliers to convert 123 pounds per mile to ounces per centimeter. There are 5,280 feet in 1 mile. There are 16 ounce

gregori [183]

A unit multiplier is a conversion factor of value 1 that we can use to convert quantities.
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First, we are going to express the quantity to convert as a fraction:
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Next, we are going to find our multipliers:
- We know for our problem that there are 5,280 feet in 1 mile, so our first multiplier will be: $\frac{1mile}{5280ft}$
- We also know that there are 16 ounces in 1 pound, so our second multiplier will be: $\frac{16ounces}{1pound}$
- We know that there are 12 inches in 1 foot, so our third multiplier will be: $\frac{1ft}{12in}$
- We know that t<span>here are approximately 2.54 cm in 1 inch, so our fourth multiplier will be: </span> $\frac{1in}{2.54cm}$

Now we can put all our multipliers together:
$123 \frac{pounds}{mile} * \frac{1mile}{5280ft}*\frac{16ounces}{1pound}* \frac{1ft}{12in}*\frac{1in}{2.54cm}=0.01 \frac{ounces}{cm}$

We can conclude that the answer is 0.01

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4 years ago

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Answer:

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Step-by-step explanation:

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