Question

An object of mass 600 kg is released from rest 1000 m above the ground and allowed to fall under the influence of gravity. Assuming the force due to air resistance is proportional to the velocity of the object with proportionality constant bequals50 ​N-sec/m, determine the equation of motion of the object. When will the object strike the​ ground? [Hint: Here the exponential term is too large to ignore. Use​ Newton's method to approximate the time t when the object strikes the​ ground.] Assume that the acceleration due to gravity is 9.81 m divided by sec squared.

Answer 1

Answer:

15 sec

Step-by-step explanation:

Data:

let m = 600 kg

    b  = 50

the differential equation will be:

$m\frac{dv}{dt} = mg - bv(t)$