Answer:
See attachment.
Step-by-step explanation:
We want to graph the linear inequality y<2
We first of all graph the corresponding linear equation y=2 with a dashed line because all points on this line do not satisfy the inequality.
We then shade below the line y=2, to show that all points below the boundary line are solution to the inequality y<2
Work shown above! Answer is
a = 144
b = 67
Recall the secant-tangent theorem, and you have
EA^2 = EC*CD
12^2 = 8*(x+10)
and now ED = EC+CD = 8+x+10
I suspect a typo somewhere in the murk above
2/3(6c+4)-(8c-5)
1) Get rid of the negative signs
New equation (the ones in bold are the changes): 2/3(6c+4)+(-8c)+(5)
2) Use distributive property for the first part by multiplying 2/3*6c= 4c and 2/3*4= 2 2/3
New equation: 4c+2 2/3+ (-8c) + 5
3) Combine like terms: 4c+(-8c)= -4c and 2 2/3+5= 7 2/3
New and simplified equation: -4c+ 7 2/3
Answer:
-2.5x-.5

draw the dotted line (3/7)x-3 and shade below it
Step-by-step explanation:
First, we need the slope
Use the slope formula:

so we have
y= -2.5x+b
Solve for b by plugging in coordiantes
-8= -2.5(3)+b
-8= -7.5+b
b= -.5
Put it together and get -2.5x-.5
2.)
A line is parallel to another line if they have the same slope (and different y intercepts)
So in the formula y=mx+b we knowe that m= 2/3
Now it's just a matter of solving for B
plug in the required coordinate to do this
-1=(2/3)*0+b
-1= b
Put it all together to get

3.)
put this into slope intercept form
3x-7y>21
3x-21 > 7y
(3/7)x-3 >y
To graph this just draw a dotted line with the equation (3/7)x-3 and shade everything below it (use de_smos if you're stuck)