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Fynjy0 [20]
4 years ago
9

Miguel wants to use coordinate geometry to prove that the opposite sides of a rectangle are congruent. He places parallelogram A

BCD in the coordinate plane so that A is (0, 0), B is (a, 0), C is (a, b), and D is (0, b).
What formula can he use to determine the distance from point A to point B?

 
Mathematics
1 answer:
solong [7]4 years ago
8 0
By graphing the given points, you will see that a rectangle can be made from the points. Points A and B lie on the same line horizontally as well as points C and D. To determine the distance between points, we use the distance formula expressed as:

d = √((y2-y1)^2 + (x2-x1)^2)

For points A and B, the term (y2-y1)^2 is equal to zero since they lie on the x-axis. The formula would become

d = √(x2-x1)^2
d = x2-x1 = a - 0 = a

Therefore, the distance would be equal to the value of a.
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Does dose anyone know how to solve this?
solniwko [45]

Answer:

Width of rectangle = 6 m

Length of rectangle = 11 m

Step-by-step explanation:

Let width of rectangle = w

Length of rectangle = 3w-7

Area of rectangle = 66 m²

We need to find length and width of rectangle

The formula used is: Area=Length \times Width

Putting values and finding w

Area=Length \times Width\\66=(3w-7)(w)\\66=3w^2-7w\\3w^2-7w-66=0\\

Solve using quadratic formula: w=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

We have a=3, b=-7, c=-66

Putting values and finding w

w=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\\w=\frac{-(-7)\pm\sqrt{(7)^2-4(3)(-66)}}{2(3)}\\w=\frac{7\pm\sqrt{49+792}}{6}\\w=\frac{7\pm\sqrt{841}}{6}\\w=\frac{7\pm29}{6}\\w=\frac{7+29}{6}\:,\:w=\frac{7-29}{6}\\w=6, w=-3.6

We get values of w as w=6 and w=-3.6

As we know width cannot be negative, so considering w = 6

So, Width = 6

Length = 3w-7 = 3(6)-7 = 18-7 = 11

So, Width of rectangle = 6 m

Length of rectangle = 11 m

6 0
3 years ago
The diameter of a large sphere is 4 times the diameter of a small sphere. The surface area of the large sphere is how many times
Sever21 [200]
Surface Area of a Sphere = 4π(d/2)²
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Small Sphere: 4π(4/2)² = 16π units²
Large Sphere: 4π(16/2)² = 256π units²

256π / 16π = 16 times

The large sphere has a surface area 16 times that of the smaller one.
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