Step-by-step explanation:
<em>Let </em><em>the </em><em>two </em><em>numbers </em><em>be </em><em>x </em><em>and </em><em>y </em>
<em>x </em><em>-</em><em> </em><em>y </em><em>=</em><em> </em><em>6</em><em>8</em><em>5</em>
<em>Let </em><em>the </em><em>smaller </em><em>number </em><em>be </em><em>y </em>
<em>x </em><em>-</em><em> </em><em>2</em><em>6</em><em>2</em><em> </em><em>=</em><em> </em><em>6</em><em>8</em><em>5</em>
<em>x </em><em>=</em><em> </em><em>6</em><em>8</em><em>5</em><em> </em><em>+</em><em> </em><em>2</em><em>6</em><em>2</em>
<em>Therefore </em><em>x </em><em>=</em><em> </em><em>9</em><em>4</em><em>7</em>
Answer:
Area = 16.8 * 7 / 2 = 58.8 ft2
Step-by-step explanation:
Have
18.2^2 = 7^2 + a^2
-> a^2 = 18.2^2 - 7^2
-> a^2 = 282.24
-> a = 16.8
Area = 16.8 * 7 / 2 = 58.8 ft2
Let's begin by listing out the information given to us:
8 am
airplane #1: x = 80870 ft, v = -450 ft/ min
airplane #2: x = 5000 ft, v = 900ft/min
1.
We must note that the airplanes are moving at a constant speed. The equation for the airplanes is given by:

2.
We equate equations 1 & 2 to get the time both airlanes will be at the same elevation. We have:

3.
The elevation at that time (when the elevations of the two airplanes are the same) is given by substituting the value of time into equations 1 & 2. We have:
For this case we must solve the following proportion:

Multiplying by 5 on both sides of the equation we have:

Subtracting 2 from both sides of the equation:

ANswer:

Answer:
x = 11
Step-by-step explanation:
The relationship between the sine and cosine functions can be written as ...
sin(x) = cos(90 -x)
sin(A) = cos(90 -A) = cos(B) . . . . substituting the given values
Equating arguments of the cosine function, we have ...
90 -(3x+4) = 8x -35
86 -3x = 8x -35
86 +35 = 8x +3x . . . . . add 3x+35 to both sides
121 = 11x . . . . . . . . . . . . collect terms
121/11 = x = 11 . . . . . . . . divide by 11
_____
<em>Comment on the solution</em>
There are other applicable relationships between sine and cosine as well. The result is that there are many solutions to this equation. One set is ...
11 +(32 8/11)k . . . for any integer k
Another set is ...
61.8 +72k . . . . . for any integer k