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ki77a [65]
3 years ago
7

To the nearest tenth, the P( -2.1 < z < 0) is:

Mathematics
1 answer:
Dvinal [7]3 years ago
5 0
-2.1 < z < 0

(-2.1 , 0)
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The difference of two numbers is 685. The smaller of the numbers is 262. What is the other number?
jeyben [28]

Step-by-step explanation:

<em>Let </em><em>the </em><em>two </em><em>numbers </em><em>be </em><em>x </em><em>and </em><em>y </em>

<em>x </em><em>-</em><em> </em><em>y </em><em>=</em><em> </em><em>6</em><em>8</em><em>5</em>

<em>Let </em><em>the </em><em>smaller </em><em>number </em><em>be </em><em>y </em>

<em>x </em><em>-</em><em> </em><em>2</em><em>6</em><em>2</em><em> </em><em>=</em><em> </em><em>6</em><em>8</em><em>5</em>

<em>x </em><em>=</em><em> </em><em>6</em><em>8</em><em>5</em><em> </em><em>+</em><em> </em><em>2</em><em>6</em><em>2</em>

<em>Therefore </em><em>x </em><em>=</em><em> </em><em>9</em><em>4</em><em>7</em>

3 0
3 years ago
Read 2 more answers
Area of the plane figure
Viefleur [7K]

Answer:

Area = 16.8 * 7 / 2 = 58.8 ft2

Step-by-step explanation:

Have

18.2^2 = 7^2 + a^2

-> a^2 = 18.2^2 - 7^2

-> a^2 = 282.24

-> a = 16.8

Area = 16.8 * 7 / 2 = 58.8 ft2

3 0
3 years ago
At 8:00 am, here's what we know about two airplanes: Airplane #1 has an elevation of 80870 ft and is decreasing at the rate of 4
wel

Let's begin by listing out the information given to us:

8 am

airplane #1: x = 80870 ft, v = -450 ft/ min

airplane #2: x = 5000 ft, v = 900ft/min

1.

We must note that the airplanes are moving at a constant speed. The equation for the airplanes is given by:

\begin{gathered} E=x_1+vt----1 \\ E=x_2+vt----2 \\ where\colon E=elevation,ft;x=InitialElevation,ft; \\ v=velocity,ft\text{/}min;t=time,min \\ x_1=80,870ft,v=-450ft\text{/}min \\ E=80870-450t----1 \\ x_2=5,000ft,v=900ft\text{/}min \\ E=5000+900t----2 \end{gathered}

2.

We equate equations 1 & 2 to get the time both airlanes will be at the same elevation. We have:

\begin{gathered} 5000+900t=80870-450t \\ \text{Add 450t to both sides, we have:} \\ 900t+450t+5000=80870-450t+450t \\ 1350t+5000=80870 \\ \text{Subtract 5000 from both sides, we have:} \\ 1350t+5000-5000=80870-5000 \\ 1350t=75870 \\ \text{Divide both sides by 1350, we have:} \\ \frac{1350t}{1350}=\frac{75870}{1350} \\ t=56.2min \\  \\ \text{After }56.2\text{ minutes, both airplanes will be at the same elevation} \end{gathered}

3.

The elevation at that time (when the elevations of the two airplanes are the same) is given by substituting the value of time into equations 1 & 2. We have:

\begin{gathered} E_1=80870-450t \\ E_1=80870-450(56.2) \\ E_1=80870-25290 \\ E_1=55580ft \\  \\ E_2=5000+900t \\ E_2=5000+900(56.2) \\ E_2=5000+50580 \\ E_2=55580ft \\  \\ \therefore E_1\equiv E_2=55580ft \end{gathered}

6 0
10 months ago
Solve for the proportion. x+2/5=6/15
Lelechka [254]

For this case we must solve the following proportion:

\frac {x + 2} {5} = \frac {6} {15}

Multiplying by 5 on both sides of the equation we have:

x + 2 = \frac {6 * 5} {15}\\x + 2 = \frac {30} {15}\\x + 2 = 2

Subtracting 2 from both sides of the equation:

x = 2-2\\x = 0

ANswer:

x = 0

8 0
3 years ago
Read 2 more answers
Please help me find x. I really don't get it.
inysia [295]

Answer:

  x = 11

Step-by-step explanation:

The relationship between the sine and cosine functions can be written as ...

  sin(x) = cos(90 -x)

  sin(A) = cos(90 -A) = cos(B) . . . . substituting the given values

Equating arguments of the cosine function, we have ...

 90 -(3x+4) = 8x -35

  86 -3x = 8x -35

  86 +35 = 8x +3x . . . . . add 3x+35 to both sides

  121 = 11x . . . . . . . . . . . . collect terms

  121/11 = x = 11 . . . . . . . . divide by 11

_____

<em>Comment on the solution</em>

There are other applicable relationships between sine and cosine as well. The result is that there are many solutions to this equation. One set is ...

  11 +(32 8/11)k . . . for any integer k

Another set is ...

  61.8 +72k . . . . . for any integer k

3 0
3 years ago
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