Answer:
A
Explanation:
I am not that sure whether is A
<span>In Drosophila + indicates wild-type allele for any gene, m is mahogany and e is ebony.
Female parents are m+/m+ and males are +e/+e.
F1 are m+/+e, all wild type. F1 females are crossed with me/me males - the test cross.
Offspring will be : non recombinant m+/me, mahogany wild type or +e/me wild type ebony. OR
recombinant me/me mahogany ebony or ++/++ wild type.
As the two genes are 25 map units apart, the percentage of recombinants will be 25% and therefore percentage parental types will be 75%.
75% 1000 is 750. There are two parental types, so you would expect 375 of each. Therefore, you would expect 375 m+/me and 375 +e/me.
25% of 1000 is 250 split between two recombinants =125 of each. Therefore you would expect 135 me/me and 125 ++/++</span>
Gastric inhibitory peptide (GIP) a digestive hormone is secreted when fats and carbohydrates, especially glucose, enter the small intestine.
- A member of the secretin family of hormones, glucose-dependent insulinotropic polypeptide is an inhibitory hormone.
- It is sometimes referred to as gastric inhibitory polypeptide or stomach inhibitory peptide.
- The enteroendocrine K-cells, which are widespread in the small intestine secrete GIP.
- The hormone gastric inhibitory polypeptide, which is released by intestinal mucosal cells, prevents the stomach from producing hydrochloric acid.
- Additionally, it improves the islets of Langerhans' beta cells' ability to secrete insulin, which results in a considerable increase in blood insulin concentrations following oral glucose delivery.
learn more about Gastric inhibitory peptide here: brainly.com/question/13048001
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Nitrogen is from the atmosphere is converted into nitrates by nitrogen fixing bacteria such as rhizobium which is found in the root nodules of leguminous crops