The claim is that the proportion of drowning deaths of children attributable to beaches is more than 0.25, and the sample statis
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Answer:
59.98
Step-by-step explanation:
To find the average of a set of numbers, we sum them all together and divide them by the size of the set. Here, we start out with 11 IQ scores. We don't know what they are, but we can still set up an equation with the information we do have. Let's call the sum of those 11 score <em>s</em>. The average must be s/11, which we know is 101.5. With that, we can set up and solve and equation for <em>s</em>:
Let's call the score of the reality TV star <em>r</em>. If we add their score to the set, we now have <em>12</em> scores. The sum of those scores is gonna be the sum of the previous scores, 1116.5, plus the reality TV star's score, r. To find the average, we divide the sum by 12. Finally, we're told that this average is exactly 98.04. Putting all of this into an equation gives us
We can now solve for r algebraically, first by multiplying both sides by 12:
And then subtracting 1116.5 from both sides:
Answer:1.69*10^12 J
Step-by-step explanation:
From figure above, using triangle ratio
485/755.5=y/l. Cross multiplying 485l=755.5y Divide via 485) hence l= 755.5y/485
Consider a slice volume Vslice= (755.5y/485)^2∆y; recall density =150lb/ft^3
Force slice = 150*755.5^2.y^2.∆y/485^2
From figure 2 in the attachment work done for elementary sclice
Wslice= 150.755.5^2.y^2.∆y.(485-y)/485^2
= (150*755.5^2*y^2)(485-y)∆y/485
To calculate the total work we integrate from y=0 to y= 485
Ie W=[ integral of 150*755.5^2 *y^2(485-y)dy/485] at y=0 and y= 485
Integrating the above
W= 150*755.5^2/485[485*y^3/3-y^4/4] at y= 0 and y=485
W= 150*755.5^2/485(485*485^3/3-484^4/4)-(485.0^3/3-0^4/4)
Work done 1.69*10^12joules
