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3 years ago

Find -2 2/5 + 4/5 need help please

Mathematics

1 answer:

diamong [38]3 years ago

4 0

Step-by-step explanation:

-22/5 +4/5

The lcm of the denominators is 5

If you divide through u have - 22+4=-18

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3 + 2x ≥ -4 solutions

erik [133]

Answer:

x ≥ -7/2

Step-by-step explanation:

3 + 2x ≥ -4

Subtract 3 from each side

3-3 + 2x ≥ -4-3

2x ≥ -7

Divide each side by 2

2x/2 ≥ -7/2

x ≥ -7/2

6 0

3 years ago

Read 2 more answers

1. What is the solution to the system below?<br> x+y=5<br> 1x- y=3

Alika [10]

Answer:

(4,1)

Step-by-step explanation:

x+y=5

x- y=3

Add the equations together to eliminate y

x+y=5

x- y=3

--------------------

2x = 8

Divide each side by 2

2x/2 = 8/2

x = 4

Now we can find y

x+y = 5

4+y = 5

Subtract 4 from each side

4+y-4 = 5-4

y =1

5 0

3 years ago

maria took 7 hours to read a 259-page book and juanita took 5 hours to read a 175-page book. who read more pages per hour? expla

Temka [501]

Answer: Maria reads more pages per hour

Step-by-step explanation:

Maria - 37 pages per hour

259 = pages read

7 = hours

259/7

Juanita - 35 pages per hour

175 = pages read

5 = hours

175/5

3 0

3 years ago

Factor f(x) = 15x^3 - 15x^2 - 90x completely and determine the exact value(s) of the zero(s) and enter them as a comma separated

Illusion [34]

Answer:

$x=-2,0,3$

Step-by-step explanation:

We have been given a function $f(x)=15x^3-15x^2-90x$ . We are asked to find the zeros of our given function.

To find the zeros of our given function, we will equate our given function by 0 as shown below:

$15x^3-15x^2-90x=0$

Now, we will factor our equation. We can see that all terms of our equation a common factor that is $15x$ .

Upon factoring out $15x$ , we will get:

$15x(x^2-x-6)=0$

Now, we will split the middle term of our equation into parts, whose sum is $-1$ and whose product is $-6$ . We know such two numbers are $-3\text{ and }2$ .

$15x(x^2-3x+2x-6)=0$

$15x((x^2-3x)+(2x-6))=0$

$15x(x(x-3)+2(x-3))=0$

$15x(x-3)(x+2)=0$

Now, we will use zero product property to find the zeros of our given function.

$15x=0\text{ (or) }(x-3)=0\text{ (or) }(x+2)=0$

$15x=0\text{ (or) }x-3=0\text{ (or) }x+2=0$

$\frac{15x}{15}=\frac{0}{15}\text{ (or) }x-3=0\text{ (or) }x+2=0$

$x=0\text{ (or) }x=3\text{ (or) }x=-2$

Therefore, the zeros of our given function are $x=-2,0,3$ .

7 0

3 years ago

Can Someone plz help me with this question? <br> I will mark brainliest

Gala2k [10]

The answer to your question is

No

8 0

2 years ago