The range for the data given is 11
Step-by-step explanation:
Equation 1: 9x + 2y = 24y, 9x = 22y, x = 22/9 y.
Equation 2: 24y = 6x + 19,
24y = 6(22/9 y) + 19
24y = 44/3 y + 19
28/3 y = 19
Hence, y = 19 * 3/28 = 57/28.
<span>2≤x≤8</span>
<span>−4≤<span>f′</span>(x)≤5</span>
f is continuous in differentable on [2,8] so we know there is c btw 2 and 8 such that
<span><span>f′</span>(c)=<span><span>f(8)−f(2)</span><span>/8−2</span></span></span>
And we know
<span>−4≤<span>f′</span>(c)≤5</span>
=> we have
<span>−4≤ <span><span>f(8)−f(2)</span><span>/8−2</span></span> ≤<span>5</span></span>
Answer:
i dont get it
Step-by-step explanation:
10w^7 is the answer I’m pretty sure
